   Chapter 6.2, Problem 6E ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
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# Using Integration Tables In Exercises 1–8, use the indicated formula from the integration table in Appendix C to find the indefinite integral. See Examples 1, 2, and 3. ∫ x 4 x 4 + 25   d x ,   Formula   23

To determine

To calculate: The solution of indefinite integral x4x4+25dx.

Explanation

Given Information:

The expression is provided as, x4x4+25dx.

Formula used:

The formula 23 from the appendix C is,

u2±a2du=12(uu2±a2±a2ln|u+u2±a2|)+C

Calculation:

Let u=2x2.

Differentiate the above equation with respect to x.

du=4xdx

Consider the provided expression,

x4x4+25dx

Multiply and divide by 4.

x4x4+25dx=144x4x4+25dx=14((2x2)2+52)4xdx

Substitute u for 2x2, and du for 4xdx

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