   Chapter 6.3, Problem 2E ### Elementary Geometry for College St...

6th Edition
Daniel C. Alexander + 1 other
ISBN: 9781285195698

#### Solutions

Chapter
Section ### Elementary Geometry for College St...

6th Edition
Daniel C. Alexander + 1 other
ISBN: 9781285195698
Textbook Problem
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# Note: Exercises preceded by an asterisk are of a more challenging nature.Given: O C = 8     a n d     O E = 6 O E ¯ ⊥ C D ¯     i n     ⊙ O Find: C D To determine

To find:

To find CD.

Explanation

Given that OC=8 and OE=6 and OE¯CD¯ in O

Consider the following figure,

Given that OE¯CD¯ in O then ΔOCE is right triangle.

Pythagorean theorem:

In a right angled triangle then the square of the hypotenuse is equal to the sum of the squares of the other two sides.

Consider the ΔOCE to get the following,

OC2=OE2+CE2

Substitute the value of OC=8 and OE=6 to get the following,

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