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Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640

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Chapter
Section
BuyFindarrow_forward

Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640
Chapter 6.3, Problem 2RC
Textbook Problem
83 views

Based on Bohr's theory, which of the following transitions for the hydrogen atom will occur with emission of visible light?

  • (a) from n = 3 to n = 1
  • (b) from n = 4 to n = 2
  • (c) from n = 5 to n = 3
  • (d) from n = 6 to n = 4

Interpretation Introduction

Interpretation: The transition for the hydrogen atom that will occur with emission of visible light is to be determined from the given option.

Concept introduction:

  • Electronic transitions that take place in excited H atom is,

    Lyman series: electronic transitions take place to the n=1 level and it is in ultraviolet region.

    Balmer series: electronic transitions take place from n>2 to the n=2 level and it is in visible region.

    Ritz-Paschen series: electronic transitions take place from n>3 to the n=3 level and it is in infrared region.

    Brackett series: electronic transitions take place from n>4 to the n=4 level.

    Pfund series: electronic transitions take place from n>5 to the n=5 level

  • Electromagnetic radiations are a type of energy surrounding us. They are of different types like radio waves, IR, UV, X-ray etc.
  • The wavelength in the visible light region of electromagnetic spectrum lies between 400nm to 700nm .

Explanation of Solution

Reason for correct option

Examine the options (b) as follows,

The option (b) explains that when electronic transitions take place in excited H atom, it emits radiation and comes to the ground state. Each electronic transition corresponds to a particular wavelength. During the transition for the hydrogen atom from n=4 to the n=2 level emits radiation with wavelength 486.1nm . This wavelength lies in the visible light region of electromagnetic spectrum which lies between 400nm to 700nm

Hence the correct option for the transition for the hydrogen atom that will occur with emission of visible light is option b.

Reasons for incorrect options:

Examine the options other than the correct ones as follows,

The option (a) explains that when electronic transitions take place in excited H atom, it emits radiation and comes to the ground state. Each electronic transition corresponds to a particular wavelength. During the transition for the hydrogen atom from n=3 to the n=1 level emits radiation with wavelength 102

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Chapter 6 Solutions

Chemistry & Chemical Reactivity
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