   Chapter 6.3, Problem 8SWU ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
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# In Exercises 7 and 8, find the absolute maximum of f on the interval. f ( x ) = 8 x 3 ' [ 1 , 2 ]

To determine

To calculate: The absolute maxima of f(x)=8x3 in the interval [1,2].

Explanation

Given Information:

The function is:

f(x)=8x3

Formula used:

The derivative of the polynomial is as:

dxndx=xn1n1

A function is said to be maximum or minimum if the derivative of that function is zero at any point in its domain.

f(x)=0

Calculation:

Consider the provided expression:

f(x)=8x3

Differentiate the above expression.

f(x)=(3)8x4=24x4

Equate the derivative 24x40 at any point in the provided domain. Therefore, there no critical points.

Now, obtain the value at the end points and at the point where function is zero

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