   Chapter 6.4, Problem 4SWU ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
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# In Exercises 1-6, find the limit (if it exists). lim x → 0 x 2 − 2 x x 3 + 3 x 2

To determine

To calculate: The limit if it exists for limx0x22xx3+3x2.

Explanation

Given Information:

The limit is provided as:

limx0x22xx3+3x2

Formula used:

The limit of a function f(x) at any point a exists if,

limxa+f(x)=f(a)=limxaf(x)

The limit of a function f(x) at any point a is expressed as:

limxaf(x)=f(a)

Calculation:

Consider the provided limit:

limx0x22xx3+3x2

Factor the denominator and numerator as;

limx0x22xx3+3x2=limx0x(x2)x2(x+3)=limx0(x2)x(x+3)

Now, calculate the left limit as the function is not defined at x=0

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