   # Calculate ∆ H for the reaction N 2 H 4 ( l ) + O 2 ( g ) → N 2 ( g ) + 2 H 2 O ( l ) given the following data: Equation ∆ H (KJ) 2NH 3 ( g ) + 3 N 2 O ( g ) → 4 N 2 ( g ) + 3 H 2 O ( l ) −1010 N 2 O ( g ) + 3 H 2 ( g ) → N 2 H 4 ( l ) + H 2 O ( l ) −317 2 NH 3 ( g ) + 1 2 O 2 ( g ) → N 2 H 4 ( l ) + H 2 O ( l ) −143 H 2 ( g ) + 1 2 O 2 ( g ) → H 2 O ( l ) −286 ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

#### Solutions

Chapter
Section ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 7, Problem 120CWP
Textbook Problem
1409 views

## Calculate ∆H for the reaction N 2 H 4 ( l ) + O 2 ( g ) → N 2 ( g ) + 2 H 2 O ( l ) given the following data: Equation ∆H(KJ) 2NH 3 ( g ) + 3 N 2 O ( g ) → 4 N 2 ( g ) + 3 H 2 O ( l ) −1010 N 2 O ( g ) + 3 H 2 ( g ) → N 2 H 4 ( l ) + H 2 O ( l ) −317 2 NH 3 ( g ) + 1 2 O 2 ( g ) → N 2 H 4 ( l ) + H 2 O ( l ) −143 H 2 ( g ) + 1 2 O 2 ( g ) → H 2 O ( l ) −286

Interpretation Introduction

Interpretation: The enthalpy change ΔH of given reaction has to be calculated and the feasibility of ammonia synthesis should be discussed.

Concept Introduction:

Hess's Law:

• The enthalpy change along with a chemical reaction is self-determining of the route by which the chemical reaction take place.
• The enthalpy change of a reaction is equal to were the reaction take place in a single step or multiple steps.

Formula:

ΔH(total)ΔH(number of steps)......(1)

Rules:

• The sign of enthalpy is inverted when the reaction is inverted.
• The amounts of reactants and products is straight comparative to the level of ΔH in a reaction. If the coefficients in a balanced reaction are multiplied by an numeral, the ΔH value is multiplied by the similar numeral.

### Explanation of Solution

Explanation

2NH3(g)+3N2O(g)4N2(g)+3H2O(l)ΔΗ=-1010KJ......(1)N2O(g)+3H2(g)N2H4(l)+H2(l)ΔΗ=-317KJ......(2)2NH3(g)+12O2(g)N2H4(l)+H2O(l)ΔH=-143KJ......(3)H2(g)+12O2(g)H2O(l)ΔΗ=-286KJ......(4)

ΔH=ΔH1+ΔH2+ΔH3+ΔH4.....(2)

ΔH=-1010+9(-286)+-3(-317)+-(-143)

The given reaction enthalpy change is:

4N2H(l)+4O2(g)4N2(g)+8H2O(l)ΔH=-2490KJN2H(l)+O2(g)®N2(g)</

### Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

#### The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

Find more solutions based on key concepts
What distinguishes an element from a compound? Can a compound also be an element?

General Chemistry - Standalone book (MindTap Course List)

What are the features of a healthy high-fat diet?

Understanding Nutrition (MindTap Course List)

Over-the-counter drugs for obesity are most often effective and pose little risk.

Nutrition: Concepts and Controversies - Standalone book (MindTap Course List)

Translate the .sequence of bases in the previous question, starting at the second base.

Biology: The Unity and Diversity of Life (MindTap Course List)

What is a standard unit?

An Introduction to Physical Science

13-38 (Chemical Connections 13A) What is meant by the term biodegradable?

Introduction to General, Organic and Biochemistry

How can errors in the cell cycle lead to cancer in humans?

Human Heredity: Principles and Issues (MindTap Course List)

What shape would the graph of U versus x have if a particle were in a region of neutral equilibrium?

Physics for Scientists and Engineers, Technology Update (No access codes included) 