Fundamentals of Biostatistics
Fundamentals of Biostatistics
8th Edition
ISBN: 9781305268920
Author: Bernard Rosner
Publisher: Cengage Learning
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Chapter 7, Problem 1P

The mean serum-creatinine level measured in 12 patients 24 hours after they received a newly proposed antibiotic was 1.2 mg/dL.

If the mean and standard deviation of serum creatinine in the general population are 1.0 and 0.4 mg/dL, respectively, then, using a significance level of .05, test whether the mean serum-creatinine level in this group is different from that of the general population.

Expert Solution & Answer
Check Mark
To determine

Check whether the mean serum-creatine level of the patients is different from that of the general population.

Answer to Problem 1P

There is no sufficient evidence that the mean serum-creatine level of the patients is different from that of the general population at 5% level of significance.

Explanation of Solution

The mean serum-creatine level of the patients is 1.2 mg/dL and the population standard deviation is 0.4 mg/dL. A sample of 12 patients is selected.

The null hypothesis is as follows:

H0:μ=1.0

The mean serum-creatine level of the patients is not different from that of the general population.

The alternative hypothesis is as follows:

H1:μ1.0

The mean serum-creatine level of the patients is different from that of the general population.

Test statistic:

The test statistic is calculated below:

z=x¯μσn=1.210.412=1.732

Critical value:

From Standard normal distribution table, the z critical values corresponding to 0.975=10.052is ±1.96.

Decision rule based on critical value approach:

If zzα2orzzα2, then reject the null hypothesis H0.

If zα2zzα2, then fail to reject the null hypothesis H0.

Conclusion based on critical value approach:

The test statistic value is given as 1.732 and critical value is ±1.96.

That is, 1.96<1.732<1.96, the test statistic lies between –1.96 and 1.96.

By the rejection rule, do not reject the null hypothesis H0.

There is no sufficient evidence that the mean serum-creatine level of the patients is different from that of the general population at 5% level of significance.

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Chapter 7 Solutions

Fundamentals of Biostatistics

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What...Ch. 7 - Consider the birthweight data in Example 7.2. Now...Ch. 7 - Prob. 89PCh. 7 - A screening program for neuroblastoma (a type of...Ch. 7 - A screening program for neuroblastoma (a type of...Ch. 7 - Prob. 92PCh. 7 - Prob. 93PCh. 7 - Prob. 94PCh. 7 - Prob. 95PCh. 7 - Prob. 96PCh. 7 - An experiment was performed to assess the efficacy...Ch. 7 - Medical errors are common in hospitals throughout...Ch. 7 - Prob. 99PCh. 7 - Prob. 100PCh. 7 - Prob. 101PCh. 7 - Prob. 102PCh. 7 - Prob. 103PCh. 7 - Prob. 104PCh. 7 - Osteoporosis is an important cause of morbidity in...Ch. 7 - Osteoporosis is an important cause of morbidity in...Ch. 7 - Osteoporosis is an important cause of morbidity in...Ch. 7 - Prob. 108PCh. 7 - Prob. 109PCh. 7 - Prob. 110PCh. 7 - Prob. 111PCh. 7 - Prob. 112PCh. 7 - Prob. 113PCh. 7 - A study was conducted in Sweden to relate the age...Ch. 7 - A study was conducted in Sweden to relate the age...Ch. 7 - A study was conducted in Sweden to relate the age...Ch. 7 - Prob. 117PCh. 7 - Prob. 118PCh. 7 - Prob. 119PCh. 7 - Prob. 120PCh. 7 - Prob. 121P
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