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College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300

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College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300
Textbook Problem

Objects with masses of 200. kg and 500. kg are separated by 0.400 m. (a) Find the net gravitational force exerted by these objects on a 50.0-kg object placed midway between them, (b) At what position (other than infinitely remote ones) can the 50.0-kg object be placed so as to experience a net force of zero?

(a)

To determine
The net gravitational force exerted on the object that placed between other two objects.

Explanation

Given info: The masses of the objects placed at right and left ends are 200kg and 500kg , the mass of the object that placed between these two objects is 50.0kg , the distance of the object that placed midway between two objects is 0.200m .

Explanation: The object with mass 500kg exerts the large force on the mass 50.0kg than the force due to the mass 200kg on the mass of 50.0kg object.

The formula for net gravitational force on the object placed in midway due to other objects is,

Fnet=Gmr2(M1M2)

  • G is gravitational constant.
  • m is the mass of the object placed in the midway.
  • M1 is the mass of the object at the right end.
  • M2 is the mass of the object at the left end.

Substitute 6.67×1011Nm2/kg2 for G , 50.0kg for m , 500kg for m2 , 200kg for m1 , and 0

(b)

To determine
The distance at which the net gravitational force acting on the object between them is zero.

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