Classify each
(a)
Interpretation:
To classify the given alkyl halide as 1°, 2°, or 3°
Concept introduction:
Alkyl halides are organic molecules that contains a halogen atom X bonded to sp3 hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.
Answer to Problem 7.1P
CH3CH2CH2CH2CH2-Br---➜ primary (1°)
Explanation of Solution
Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.
primary (1°) = one carbon attached to carbon with halogen
secondary (2°) = two carbon attached to carbon with halogen
tertiary (3°) = three carbon attached to carbon with halogen
CH3CH2CH2CH2CH2-Br---➜ in this structure only one carbon attached to carbon with halogen so primary (1°)
Thus the given structure is primary (1°)
(b)
Interpretation:
To classify the given alkyl halide as 1°, 2°, or 3°
Concept introduction:
Alkyl halides are organic molecules that contains a halogen atom X bonded to sp3 hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.
Answer to Problem 7.1P
------------➜ tertiary (3°)
Explanation of Solution
Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.
primary (1°) = one carbon attached to carbon with halogen
secondary (2°) = two carbon attached to carbon with halogen
tertiary (3°) = three carbon attached to carbon with halogen
---➜ in this structure three carbons attached to carbon with halogen so primary (1°)
Thus the given structure is tertiary (3°)
(c)
Interpretation:
To classify the given alkyl halide as 1°, 2°, or 3°
Concept introduction:
Alkyl halides are organic molecules that contains a halogen atom X bonded to sp3 hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.
Answer to Problem 7.1P
------------➜ secondary (2°)
Explanation of Solution
Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.
primary (1°) = one carbon attached to carbon with halogen
secondary (2°) = two carbon attached to carbon with halogen
tertiary (3°) = three carbon attached to carbon with halogen
---➜ in this structure two carbons attached to carbon with halogen so secondary (2°)
Thus the given structure is secondary (2°)
(d)
Interpretation:
To classify the given alkyl halide as 1°, 2°, or 3°
Concept introduction:
Alkyl halides are organic molecules that contains a halogen atom X bonded to sp3 hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.
Answer to Problem 7.1P
------------➜ tertiary (3°)
Explanation of Solution
Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.
primary (1°) = one carbon attached to carbon with halogen
secondary (2°) = two carbon attached to carbon with halogen
tertiary (3°) = three carbon attached to carbon with halogen
---➜ in this structure three carbons attached to carbon with halogen so tertiary (3°)
Thus the given structure is tertiary (3°)
Want to see more full solutions like this?
Chapter 7 Solutions
ORGANIC CHEMISTRY-STUDY GDE...-W/ACCESS