ORGANIC CHEMISTRY-STUDY GDE...-W/ACCESS
ORGANIC CHEMISTRY-STUDY GDE...-W/ACCESS
4th Edition
ISBN: 9780078051555
Author: SMITH
Publisher: MCG
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Textbook Question
Chapter 7, Problem 7.1P

Classify each alkyl halide as 1 °, 2°, or 3°.

Chapter 7, Problem 7.1P, Classify each alkyl halide as 1 , 2, or 3.

Expert Solution
Check Mark
Interpretation Introduction

(a)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp3 hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

CH3CH2CH2CH2CH2-Br---➜ primary (1°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

CH3CH2CH2CH2CH2-Br---➜ in this structure only one carbon attached to carbon with halogen so primary (1°)

Conclusion

Thus the given structure is primary (1°)

Expert Solution
Check Mark
Interpretation Introduction

(b)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp3 hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

ORGANIC CHEMISTRY-STUDY GDE...-W/ACCESS, Chapter 7, Problem 7.1P , additional homework tip  1------------➜ tertiary (3°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

ORGANIC CHEMISTRY-STUDY GDE...-W/ACCESS, Chapter 7, Problem 7.1P , additional homework tip  2---➜ in this structure three carbons attached to carbon with halogen so primary (1°)

Conclusion

Thus the given structure is tertiary (3°)

Expert Solution
Check Mark
Interpretation Introduction

(c)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp3 hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

ORGANIC CHEMISTRY-STUDY GDE...-W/ACCESS, Chapter 7, Problem 7.1P , additional homework tip  3------------➜ secondary (2°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

ORGANIC CHEMISTRY-STUDY GDE...-W/ACCESS, Chapter 7, Problem 7.1P , additional homework tip  4

---➜ in this structure two carbons attached to carbon with halogen so secondary (2°)

Conclusion

Thus the given structure is secondary (2°)

Expert Solution
Check Mark
Interpretation Introduction

(d)

Interpretation:

To classify the given alkyl halide as 1°, 2°, or 3°

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp3 hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

Answer to Problem 7.1P

ORGANIC CHEMISTRY-STUDY GDE...-W/ACCESS, Chapter 7, Problem 7.1P , additional homework tip  5------------➜ tertiary (3°)

Explanation of Solution

Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen.

primary (1°) = one carbon attached to carbon with halogen

secondary (2°) = two carbon attached to carbon with halogen

tertiary (3°) = three carbon attached to carbon with halogen

ORGANIC CHEMISTRY-STUDY GDE...-W/ACCESS, Chapter 7, Problem 7.1P , additional homework tip  6

---➜ in this structure three carbons attached to carbon with halogen so tertiary (3°)

Conclusion

Thus the given structure is tertiary (3°)

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Chapter 7 Solutions

ORGANIC CHEMISTRY-STUDY GDE...-W/ACCESS

Ch. 7 - Prob. 7.11PCh. 7 - Prob. 7.12PCh. 7 - Does the equilibrium favor the reactants or...Ch. 7 - Prob. 7.14PCh. 7 - Prob. 7.15PCh. 7 - Classify each solvent as protic or aprotic. a. b....Ch. 7 - Prob. 7.17PCh. 7 - Prob. 7.18PCh. 7 - Prob. 7.19PCh. 7 - Prob. 7.20PCh. 7 - Prob. 7.21PCh. 7 - Draw an energy diagram for the reaction in Problem...Ch. 7 - Draw the product of each SN2 reaction and indicate...Ch. 7 - Prob. 7.24PCh. 7 - Prob. 7.25PCh. 7 - What happens to the rate of an SN1 reaction under...Ch. 7 - Draw the products of each SN1 reaction and...Ch. 7 - Classify each carbocation as 1,2, or 3. a. b. c....Ch. 7 - Prob. 7.29PCh. 7 - Prob. 7.30PCh. 7 - Which alkyl halide in each pair reacts faster in...Ch. 7 - Prob. 7.32PCh. 7 - Problem 7.30 For each alkyl halide and...Ch. 7 - Prob. 7.34PCh. 7 - Prob. 7.35PCh. 7 - Prob. 7.36PCh. 7 - Prob. 7.37PCh. 7 - Prob. 7.38PCh. 7 - Prob. 7.39PCh. 7 - Prob. 7.40PCh. 7 - Prob. 7.41PCh. 7 - Give the IUPAC name for each compound, including...Ch. 7 - Draw the products formed when each alkyl halide is...Ch. 7 - Give the IUPAC name for each compound. a. c....Ch. 7 - Prob. 7.45PCh. 7 - Classify each alkyl halide in Problem 7.44 as 1 ,...Ch. 7 - Draw the eight constitutional isomers having the...Ch. 7 - Prob. 7.48PCh. 7 - Draw the substitution product that results when...Ch. 7 - Draw the products of each nucleophilic...Ch. 7 - Prob. 7.51PCh. 7 - Rank the species in each group in order of...Ch. 7 - Which of the following nucleophilic substitution...Ch. 7 - Prob. 7.54PCh. 7 - Prob. 7.55PCh. 7 - Prob. 7.56PCh. 7 - 7.53 Consider the following reaction. Draw a...Ch. 7 - Prob. 7.58PCh. 7 - Prob. 7.59PCh. 7 - Draw the products of each SN2 reaction and...Ch. 7 - Prob. 7.61PCh. 7 - Prob. 7.62PCh. 7 - Prob. 7.63PCh. 7 - Consider the following SN1 reaction. a.Draw a...Ch. 7 - Prob. 7.65PCh. 7 - Prob. 7.66PCh. 7 - Draw the products of each SN1 reaction and...Ch. 7 - Prob. 7.68PCh. 7 - Prob. 7.69PCh. 7 - Diphenhydramine, the antihistamine in Benadryl,...Ch. 7 - Draw a stepwise, detailed mechanism for the...Ch. 7 - When a single compound contains both a nucleophile...Ch. 7 - Prob. 7.73PCh. 7 - Prob. 7.74PCh. 7 - Draw a stepwise, detailed mechanism f or the...Ch. 7 - Prob. 7.76PCh. 7 - Fill in the appropriate reagent or starting...Ch. 7 - Devise a synthesis of each compound from an alkyl...Ch. 7 - Prob. 7.79PCh. 7 - Suppose you have compounds A-D at y our disposal....Ch. 7 - Prob. 7.81PCh. 7 - Prob. 7.82PCh. 7 - Prob. 7.83PCh. 7 - Prob. 7.84PCh. 7 - 7.80 As we will learn in Chapter 9, an epoxide is...Ch. 7 - Prob. 7.86PCh. 7 - In some nucleophilic substitutions under SN1...
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