Let J S = { 0 , 1 , 2 , 3 , 4 } ,and define G : J s × J s → J s × J s as follows: For each ( a , b ) ∈ J s × J s , G ( a , b ) = ( ( 2 a + 1 ) mod 5 , ( 3 b − 2 ) mod 5 ) . Find the following: a. G ( 4 , 4 ) b. G ( 2 , 1 ) c. G ( 3 , 2 ) d. G ( 1 , 5 )
Let J S = { 0 , 1 , 2 , 3 , 4 } ,and define G : J s × J s → J s × J s as follows: For each ( a , b ) ∈ J s × J s , G ( a , b ) = ( ( 2 a + 1 ) mod 5 , ( 3 b − 2 ) mod 5 ) . Find the following: a. G ( 4 , 4 ) b. G ( 2 , 1 ) c. G ( 3 , 2 ) d. G ( 1 , 5 )
Solution Summary: The objective is to determine the value of G(4,4).
Let
J
S
=
{
0
,
1
,
2
,
3
,
4
}
,and define
G
:
J
s
×
J
s
→
J
s
×
J
s
as follows: For each
(
a
,
b
)
∈
J
s
×
J
s
,
G
(
a
,
b
)
=
(
(
2
a
+
1
)
mod
5
,
(
3
b
−
2
)
mod
5
)
.
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, subject and related others by exploring similar questions and additional content below.
RELATIONS-DOMAIN, RANGE AND CO-DOMAIN (RELATIONS AND FUNCTIONS CBSE/ ISC MATHS); Author: Neha Agrawal Mathematically Inclined;https://www.youtube.com/watch?v=u4IQh46VoU4;License: Standard YouTube License, CC-BY