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Math
GeometryElementary Geometry for College Students6th Edition

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Chapter 7.1, Problem 45E
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Elementary Geometry for College St...

6th Edition
Daniel C. Alexander + 1 other
ISBN: 9781285195698

Solutions

Chapter
Section
Problem 1E
Problem 2E
Problem 3E
Problem 4E
Problem 5E
Problem 6E
Problem 7E
Problem 8E
Problem 9E
Problem 10E
Problem 11E
Problem 12E
Problem 13E
Problem 14E
Problem 15E
Problem 16E
Problem 17E
Problem 18E
Problem 19E
Problem 20E
Problem 21E
Problem 22E
Problem 23E
Problem 24E
Problem 25E
Problem 26E
Problem 27E
Problem 28E
Problem 29E
Problem 30E
Problem 31E
Problem 32E
Problem 33E
Problem 34E
Problem 35E
Problem 36E
Problem 37E
Problem 38E
Problem 39E
Problem 40E
Problem 41E
Problem 42E
Problem 43E
Problem 44E
Problem 45E
Problem 46E
BuyFindarrow_forward

Elementary Geometry for College St...

6th Edition
Daniel C. Alexander + 1 other
ISBN: 9781285195698
Textbook Problem
1 views

In Exercises 39 and 42, refer to the line segments shown.

Use the following theorem to construct a triangle similar to the given triangle but with sides that are twice the length of those of the given triangle.

Theorem: If the lengths of the three pairs of sides for two triangles are in proportion, then those triangles are similar (SSS˜).

Chapter 7.1, Problem 45E, In Exercises 39 and 42, refer to the line segments shown. Use the following theorem to construct a

To determine

To construct:

The triangle similar to the given triangle but with sides that are twice the length of those of the given triangle.

Explanation

Theorem:

If the lengths of the three pairs of sides for two triangles are in proportion, then those triangles are similar.

Calculation:

Construct the given triangle ABC as shown in figure.

To construct a triangle similar to ABC but twice the size, follow the below procedure:

1. Take any arbitrary point Y and draw a horizontal line XZ equal to twice the length of BC.

2. Take Y as center and draw an arc equal to twice the length of AB above the line YZ and take Z as center and draw an arc equal to twice the length of AC above the line YZ to obtain the intersection point X.

3. Draw the lines XY and XZ to obtain the triangle twice the size of the triangle ABC as shown below:

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Sect-7.1 P-1ESect-7.1 P-2ESect-7.1 P-3ESect-7.1 P-4ESect-7.1 P-5ESect-7.1 P-6ESect-7.1 P-7ESect-7.1 P-8ESect-7.1 P-9ESect-7.1 P-10E
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