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Discrete Mathematics With Applicat...

5th Edition
EPP + 1 other
ISBN: 9781337694193

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BuyFindarrow_forward

Discrete Mathematics With Applicat...

5th Edition
EPP + 1 other
ISBN: 9781337694193
Textbook Problem
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Each of exercises 51-53 refers to the Euler phi function, denoted ϕ , which is defined as follows: For each integer n 1 , ϕ ( n ) is the number of positive integers less than or equal to n that have no common factors with n except ± 1 . For example, ϕ ( 10 ) = 4 because there are four positive integers less than or equal to 10 that have no common factor with 10 except ± 1 -namely, 1,3,7, and9.

Prove that if p is a prime number and n is an integer with n 1 , then ϕ ( p n ) = p n p n 1 .

To determine

To Prove:

When p is a prime number and n is an integer with n1, then

ϕ(pn)=pnpn1

Explanation

Given information:

p is a prime number and n is an integer with n1.

Concept used:

There are pn1 integers between 1 and pn divisible by p.

Proof:

The positive integers less than pn and co-prime to pn are different from the divisors of pn.

p,2p,3p,........,pn1p are the divisors of pn. These are pn1 in number

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