   Chapter 7.1, Problem 8SWU ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
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# In Exercises 7 and 8, find the standard form of the equation of the circle with the given characteristics.Endpoints of a diameter: (4, 0), (-2, 8)

To determine

To calculate: The standard equation of circle if end point of diameter of the circle is (4,0) and (2,8).

Explanation

Given information:

The end point of diameter of the circle are (4,0) and (2,8).

Formula used:

Standard equation of circle, if (x1,y1) is the center of the circle and r is radius,

(xx1)2+(yy1)2=r2

Calculation:

Consider the end point of the circle, (4,0) and (2,8).

Since, the middle point of the diameter of the circle is center of the circle. So, find the midpoint of the endpoint of the diameter of a circle,

Midpoint=(4+(2)2,8+02)=(1,4)

Thus, the center of circle is (1,4).

Since, the distance between the center to the circumference of a circle is equal to the radius of the circle

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