   Chapter 7.2, Problem 7E

Chapter
Section
Textbook Problem

# Evaluate the integral. ∫ 0 π / 2 cos 2 θ   d θ

To determine

To evaluate: The trigonometric integral 0π2cos2θdθ

Explanation

Trigonometric integral of the form sinmxcosnxdx can be solved using strategies depending on whether m and n are odd or even.

Formula used:

cos2θ=2cos2θ1

Given:

The integral, 0π2cos2θdθ.

Calculation:

Use the identity cos2θ=2cos2θ1 to substitute for square of cosine function:

0π2cos2θdθ=0π2(cos2θ+1)2dθ=120π2(cos2θ+1

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