   Chapter 7.4, Problem 41E ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
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# Using First Partial Derivatives In Exercises 41-44, find all values of x and y such that f x ( x , y ) = 0 and f y ( x , y ) = 0 simultaneously. f ( x , y ) = x 2 + 4 x y + y 2 − 4 x + 16 y + 3

To determine

To calculate: The all value of x and y from the function f(x,y)=x2+4xy+y24x+16y+3 such that fx(x,y)=0 and fy(x,y)=0 simultaneously.

Explanation

Given information:

The provided function is f(x,y)=x2+4xy+y24x+16y+3 and the condition is fx(x,y)=0 and fy(x,y)=0 simultaneously.

Formula used:

Consider the function z=f(x,y) then for the value of zx consider y to be constant and differentiate with respect to x and the value of zy consider x to be constant and differentiate with respect to y.

Calculation:

Consider the provided function is,

f(x,y)=x2+4xy+y24x+16y+3

Partially derivative of the function f(x,y)=x2+4xy+y24x+16y+3 with respect to x.

fx(x,y)=x(x2+4xy+y24x+16y+3)=x(x2)+4yx(x)+y2x(1)4x(x)+16yx(1)+x(3)=2x+4y4

Substitute 0 for fx(x,y).

2x+4y4=02x+4y=4x+2y=2 …...…... (1)

Partially derivative of the function f(x,y)=x2+4xy+y24x+16y+3 with respect to y

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