   Chapter 7.5, Problem 15QY ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
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# In Exercises 13-15, find f(1, 0) and f(4, -1). f ( x , y ) = ln ( x − 2 y )

To determine

To calculate: The values of f(1,0) and f(4,1) for the function f(x,y)=ln(x2y).

Explanation

Given Information:

The provided function is f(x,y)=ln(x2y).

Calculation:

Consider the function, f(x,y)=ln(x2y)

The value of x and y for f(1,0) are 1 and 0 respectively.

Substitute x=1 and y=0 in the equation f(x,y)=ln(x2y),

f(1,0)=ln(120)=ln(10)=ln1=0

The value of x and y for f(4,1) are 4 and 1 respectively

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