   Chapter 7.5, Problem 46E

Chapter
Section
Textbook Problem

# Evaluate the integral. ∫ ( x − 1 ) e x x 2 d x

To determine

To find:

x-1exx2dx

Explanation

Formula used:

Integration by parts: udv= uv-vdu1x2dx=-1x+c

Calculations: Simplifying the given integral I we get

We shall use integration by parts with u=(x-1)ex and dv=1x2 Then du=((x-1)ex+ex)dx = xexdx and v=-1x Then I= x-1exx2dx =udv= uv-vdu

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