X1 - 3x3: 3x3 = 8 2x1 + 2x2 + 9хз — 7 X2 + 5хз — —2

College Algebra
10th Edition
ISBN:9781337282291
Author:Ron Larson
Publisher:Ron Larson
ChapterP: Prerequisites
SectionP.3: Polynomials And Special Products
Problem 4ECP: Multiply x2+2x+3 by x22x+3 using a vertical arrangement.
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solve the system in exercises 11-14

X1
- 3x3:
3x3 =
8
2x1 + 2x2 + 9хз —
7
X2 + 5хз — —2
Transcribed Image Text:X1 - 3x3: 3x3 = 8 2x1 + 2x2 + 9хз — 7 X2 + 5хз — —2
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