   Chapter 7.5, Problem 5SWU ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
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# In Exercises 1-8, solve the system of equations. { x − 2 y = 4 5 x − 3 y = 13

To determine

To calculate: The solution of system of equations x2y=4 and 5x3y=13.

Explanation

Given Information:

The system of equations is:

x2y=45x3y=13

Formula used:

Pair of linear equation (linear) in two variables

a1x+b1y=c1a2x+b2y=c2

A system of linear equation can be solved using the method of elimination. To solve the system of equation using elimination follow the following procedure.

Step 1: Arrange both equations such that the like variables and constants are one above the other.

Step 2: Decide which variable to eliminate and with proper choice of multiplication, arrange so that the coefficients of that variable are same or opposite in sign for another.

Step 3: Add the equations if they are of opposite sign and subtract the equations if they are same sign leaving one equation with one variable.

Step 4: Solve for the remaining one variable.

Step 5: Substitute the value found in the above step in any equation involving both variables and solve for the other variable.

Calculation:

Consider the given equation

x2y=45x3y=13

The system of equations can be solved using the method of elimination.

Eliminating x, by multiplying 5 to the first equation and then subtracting with second equation.

5x10y=205x3y=137y=7

Divide both sides by 7:

7y7=77y=1

Substituting the value of y=1 in equation x

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