   Chapter 7.5, Problem 70E

Chapter
Section
Textbook Problem

# Evaluate the integral. ∫ 1 1 + 2 e x − e − x d x

To determine

To find:

11+2ex-e-xdx

Explanation

Formula used: 1. dxx2-a2=12alnx-ax+a

Calculations: In the given integral I, multiply the numerator and denominator by ex

I=exex+2e2x-1dx

Let us now suppose ex=t, then exdx=dt

The integral can now be written as

I=dt2t2+t-1=12dtt2+t2-12+142-14

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