   Chapter 7.6, Problem 15E ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
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# Using Lagrange Multipliers In Exercises 13-18, use Lagrange multipliers to find the indicated extremum. Assume that x, y, and z are positive. See Example 1.Minimize f ( x , y , z )   =   x 2 +   y 2 +   z 2 Constraint: x + y   +   z =   1

To determine

To calculate: The extremum of the function f(x,y,z)=x2+y2+z2 subjected to the constraint

g(x,y,z)=x+y+z1=0.

Explanation

Given Information:

The function f(x,y,z)=x2+y2+z2 subject to the constraint g(x,y,z)=x+y+z1 and x, y, z are positive numbers.

Formula used:

If f(x,y,z) has a maximum or minimum subject to the constraint g(x,y,z)=0, then it will

take at one of the critical points of the function F defined as:

F=f(x,y,z)λg(x,y,z)

The variable λ is called the Lagrange Multiplier. To find the maximum or minimum of f follow

the given steps:

Step 1: Solve the following system of equations:

Fx(x,y,z,λ)=0Fy(x,y,z,λ)=0Fz(x,y,z,λ)=0Fλ(x,y,z,λ)=0

Step 2: Calculate f at each solution point get from the first step. The greatest value yields maximum of f and the smallest value yields minimum of f subject to the constraint g(x,y,z)=0.

Calculation:

Consider the given equations

f(x,y,z)=x2+y2+z2g(x,y,z)=x+y+z1=0

Now, consider the primary equation

F=f(x,y,z)λg(x,y,z)F=x2+y2+z2λ(x+y+z1)

For critical numbers of F, differentiate F with respect to x, y, z then set it equal to zero

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