   Chapter 7.6, Problem 32E

Chapter
Section
Textbook Problem

# Use the Table of Integrals on Reference Pages 6–10 to evaluate the integral. ∫ sec 2 θ tan 2 θ 9 − tan 2 θ d θ

To determine

To evaluate:

sec2θtan2θ9tan2θdθ

Explanation

Given:

sec2θtan2θ9tan2θdθ

Calculation:

Let u=tanθ,du=sec2θdθ, and a=3, then

sec2θtan2θ9tan2θdθ=u2a2u2du

From Table of integrals, entry no 34, we have

u2a2u2du=u2a2u2+a22sin1(ua)+C

u2a2u

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