   Chapter 7.6, Problem 6SWU ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
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# In Exercises 1-6, solve the system of linear equations. { 3 x + 4 y + z = 2 x − 2 y − 2 z = − 7 4 x − 6 y + 4 z = 0

To determine

To calculate: The values of x,y,z for the equations 3x+4y+z=2,x2y2z=7 and4x6y+4z=0

Explanation

Given Information:

The equations 3x+4y+z=2,x2y2z=7 and4x6y+4z=0

Formula used:

Step 1: Calculate the value z from given equation in form of x and y.

Step 2: And from one of those equation calculate value of y in terms of x and put in the last

one and get the value of x.

Step 3: By using the value of x will get the value of y and z as well.

Calculation:

Consider the given equation

3x+4y+z=2 …… (1)

x2y2z=7 …… (2)

4x6y+4z=0 …… (3)

From equation (1)

3x+4y+z=2z=23x4y

Now, from equation (2),

x2y2(23x4y)=7x2y4+6x+8y=77x+6y=7+4=37x+6y=3

And,

x=36y7

And, from equation (3)

4x6y+4(23x4y)=04x6y+812x16y=0

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