   Chapter 7.8, Problem 2SWU ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
3 views

# In Exercises 1-12, evaluate the definite integral. ∫ 0 2 3   d y

To determine

To calculate: The value of definite integral is 023dy.

Explanation

Given Information:

The definite integral is 023dy.

Formula used:

If, x is lower limit and x2 is upper limit then for the above function.

x1x2axndx=a[xn+1n+1]x1x2x=a[x2n+1x1n+1n+1]

Calculation:

Finding the function f(x)=axn

At a=3 , n=0 and x=y

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