   Chapter 7.R, Problem 16E

Chapter
Section
Textbook Problem

# Evaluate the integral. ∫ sec 6 θ tan 2 θ d θ

To determine

To Find: sec6θtan2θdθ

Explanation

The above integration can be solved by using trigonometry integration rule.

Calculation:

sec6θtan2θdθ=sec4θsec2θtan2θdθ=(1+tan2θ)2sec2θtan2θdθ

The solution of the above integral is given by

Let u=tanθ then du=sec2θsec4θsec2θtan2θdθ=(<

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