   Chapter 7.R, Problem 5E

Chapter
Section
Textbook Problem

# Evaluate the integral. ∫ d t 2 t 2 + 3 t + 1

To determine

To Find: 12t2+3t+1dt

Explanation

We solve the above integration by using partial fraction. Now the partial fractions are

1(2t+1)(t+1)dt=A2t+1+B1+t

Calculation:1=A(1+t)+B(1+2t). Put like term together and you get A+B=1andA+2B=0 to solve the system of equation. Let A=1B and put it into the A+2B=0 and we get 1B+2B=0 and we can solve for B and we get B=1. Now put this into A+B=1 and we get A=2

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