   # Freon−12 is used as a refrigerant in central home air conditioners. The rate of effusion of Freon-12 to Freon-11 (molar mass = 137.4 g/mol) is 1.07:1. The formula of Freon-12 is one of the following: CF 4 , CF 3 C1, CF 2 C1 2 , CFC1 3 , or CC1 4 . Which formula is correct for Freon-12? ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

#### Solutions

Chapter
Section ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 8, Problem 111E
Textbook Problem
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## Freon−12 is used as a refrigerant in central home air conditioners. The rate of effusion of Freon-12 to Freon-11 (molar mass = 137.4 g/mol) is 1.07:1. The formula of Freon-12 is one of the following: CF4, CF3C1, CF2C12, CFC13, or CC14. Which formula is correct for Freon-12?

Interpretation Introduction

Interpretation: For the given formulas, the correct formula of Freon-12 should be identified.

Concept introduction:

Effusion is used to describe the passage of a gas through a tiny particle into an evacuated chamber.

The rate of effusion is the measure speed at which the gas is transferred to the chamber.

According to Thomas Graham the rate of effusion of a gas is inversely proportional to the square root of the mass of its particles.

The relative rate of effusion of two gases at the same temperature and pressure are the inverse ratio of the square root of the masses of the gases particles. That is,

Rateofeffusionforgas1Rateofeffusionforgas2=M2M1orRate1Rate2=(M2M1)1/2

M1andM2arethemolarmassesoftwogases

This equation is known as Graham’s law of effusion.

### Explanation of Solution

Explanation

To determine: the molar mass of Freon-12

Molar mass of Freon-12 is 121 g/mol

According to Graham’s law of effusion,

Rate1Rate2=(M2M1)1/2

Here,Gas1=Freon-12Gas2=Freon-11M2=molarmassofFreon-11=137.4g/molM1=molarmassofFreon-12Rate1Rate2=(M2M1)1/2Since,therateofeffusionofFreon-12toFreon-11is1.07:1So,1.071.00=(137.4M1)1/21.14=137

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