(a) Interpretation: The number of molecules present in 3.45 g of C 6 H 12 O 6 should be calculated. Concept Introduction: According to Avogadro’s number, one mole of a compound contains 6.023 × 10 23 molecules. Number of moles of a compound is calculated by dividing the given mass of the compound by its molar mass. Moles = M a s s M o l a r M a s s .

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Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781337399425
BuyFind

Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781337399425

Solutions

Chapter 8, Problem 116AP
Interpretation Introduction

(a)

Interpretation:

The number of molecules present in 3.45 g of C6H12O6 should be calculated.

Concept Introduction:

According to Avogadro’s number, one mole of a compound contains 6.023×1023 molecules.

Number of moles of a compound is calculated by dividing the given mass of the compound by its molar mass.

Moles=MassMolarMass.

Interpretation Introduction

(b)

Interpretation:

The number of molecules present in 3.45 moles of C6H12O6 should be calculated.

Concept Introduction:

According to Avogadro’s number, one mole of a compound contains 6.023×1023 molecules.

Interpretation Introduction

(c)

Interpretation:

The number of molecules present in 25 g of ICl5 should be calculated.

Concept Introduction:

According to Avogadro’s number, one mole of a compound contains 6.023×1023 molecules.

Number of moles of a compound is calculated by dividing the given mass of the compound by its molar mass.

Moles=MassMolarMass.

Interpretation Introduction

(d)

Interpretation:

The number of molecules present in 1g of B2H6 should be calculated.

Concept Introduction:

According to Avogadro’s number, one mole of a compound contains 6.023×1023 molecules.

Number of moles of a compound is calculated by dividing the given mass of the compound by its molar mass.

Moles=MassMolarMass.

Interpretation Introduction

(e)

Interpretation:

The number of molecules present in 1.05 mmol of Al(NO3)3 should be calculated.

Concept Introduction:

According to Avogadro’s number, one mole of a compound contains 6.023×1023 molecules.

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