A spherical glass container of unknown volume contains helium gas at 25°C and 1.960 atm. When a portion of the helium is withdrawn and adjusted to 1.00 atm at 25°C, it is found to have a volume of 1.75 cm 3 . The gas remaining in the first container shows a pressure of 1.710 atm. Calculate the volume of the spherical container.

Q: Expert Answer

Interpretation Introduction Interpretation: For the given data, volume of the spherical container should be determined. Concept introduction: By combining the three gaseous laws namely Boyle’s law, Charles’s law and Avogadro’s law a combined gaseous equation is obtained. This combined gaseous equation is called Ideal gas law . According to ideal gas law, PV=nRT Where, P = pressure in atmospheres V= volumes in liters n = number of moles R =universal gas constant ( 0 .08206L×atm/K×mol ) T = temperature in kelvins By knowing any three of these properties, the state of a gas can be simply identified with applying the ideal gas equation. Number of moles of gas can be calculated from the ideal gas equation is as follows, n = P V R T Volume of the gas can be determined from the ideal gas equation as follows, V = n R T P Explanation Explanation To determine: the number of moles of He removed Number of moles of He removed 7 . 1 6 × 1 0 - 5 m o l According to ideal gas equation, P V = n R T Number of moles of gas can be calculated from the ideal gas equation is as follows, n = P V R T From the given data,to calculate the mol of He removed, P= 1 atm V =1 .75 cm 3 = 1 .75 ×10 -3 L Since,1L= 1000cm 3 R = 0 .08206L×atm K×mol T = 25°C =298 K Since,K = ( °C+273 ) K = ( 25°C+273 ) K =298 K n = 1 .00atm×1 .75 ×10 -3 L 0 .08206L×atm K×mol ×298K = 7

Question

Still sussing out bartleby?

Answer 1

BuyFind

Chemistry: An Atoms First Approach

2nd Edition

Steven S. Zumdahl + 1 other

Publisher: Cengage Learning

ISBN: 9781305079243

Solutions

Chapter

Section

Answer 2

BuyFind

Chemistry: An Atoms First Approach

2nd Edition

Steven S. Zumdahl + 1 other

Publisher: Cengage Learning

ISBN: 9781305079243

Solutions

Chapter

Section

Answer 3

Solutions

Chapter

Section

Answer 4

Chapter

Section

Answer 5

Interpretation Introduction

Interpretation: For the given data, volume of the spherical container should be determined.

Concept introduction:

By combining the three gaseous laws namely Boyle’s law, Charles’s law and Avogadro’s law a combined gaseous equation is obtained. This combined gaseous equation is called Ideal gas law.

According to ideal gas law,

PV=nRT

Where,

P = pressure in atmospheres

V= volumes in liters

n = number of moles

R =universal gas constant ( 0.08206L×atm/K×mol )

T = temperature in kelvins

By knowing any three of these properties, the state of a gas can be simply identified with applying the ideal gas equation.

Number of moles of gas can be calculated from the ideal gas equation is as follows,

n=PVRT

Volume of the gas can be determined from the ideal gas equation as follows,

V= n RTP

Explanation of Solution

Explanation

To determine: the number of moles of He removed

Number of moles of He removed 7.16 ×10 -5mol

According to ideal gas equation,

PV=nRT

Number of moles of gas can be calculated from the ideal gas equation is as follows,

n=PVRT

From the given data,to calculate the mol of He removed,P= 1 atmV =1.75 cm3= 1.75 ×10-3 L Since,1L= 1000cm3R =0.08206L×atmK×molT = 25°C =298 K Since,K =(°C+273)K = (25°C+273)K =298 Kn =1.00atm×1.75 ×10-3 L0.08206L×atmK×mol×298K = 7

Chemistry: An Atoms First Approach

Solutions

Chemistry: An Atoms First Approach

Explanation of Solution

Still sussing out bartleby?

The Solution to Your Study Problems

Chapter 8 Solutions

Additional Science Textbook Solutions