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College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300

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College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300
Textbook Problem

A cook holds a 2.00-kg carton of milk at arm's length P8.19). What force F B must be exerted by the biceps muscle? (Ignore the weight of the forearm.)

images

Figure P8.19

To determine
The force exerted by the biceps muscle.

Explanation

Given info: The mass of the carton of milk is 2.00kg , the acceleration due to gravity is 9.80m/s2 , the length of the arm from the left side of the pivot point is 25.0cm , the length of the arm from right side of the pivot point is 8.00cm , the angle of the force by the biceps is 75.0° .

Explanation: At equilibrium condition, the sum of torques on her arm length is τ=0=(l1+l2)mgl2FBcosθ by ignoring the weight of the forearm.

The formula for the force exerted by the biceps muscle is,

FB=(l1+l2)mgl2cosθ

  • l1 is length of the arm from the left side of the pivot point.
  • l2 is length of the arm from right side of the pivot point.
  • m is mass of the carton of milk.
  • g is acceleration due to gravity.
  • θ is angle of the force by the biceps

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