Chapter 8, Problem 1CR

To determine

To find: the value of $t$ when $s=28$ .

Answer to Problem 1CR

The value is $t=49$ when $s=28$ .

Explanation of Solution

Given information:

The value $t=21$ when $s=12$ .

Calculation: since, $t=21$ when $s=12$ so relation can be defined as:

  $\begin{array}{l}t=ks\\ 21=k\left(12\right)\text{ [substitute]}\\ k=\frac{21}{12}\text{ [divide]}\\ k=\frac{7}{4}\text{ [simplify]}\end{array}$

Now, to find the value of $t$ , substitute and simplify,

  $\begin{array}{l}t=ks\\ t=\frac{7}{4}\left(28\right)\text{ [susbtitute]}\\ t=49\text{ [simplify]}\end{array}$

Thus, The value is $t=49$ when $s=28$ .