Chapter 8, Problem 1E

Explanation of Solution

“quadrant” method:

//definition of "Point" class

public class Point

{

    //declare the required variables

    int x;

    int y;

    //definition of "quadrant" method

    public int quadrant()

    {

        //check "x" and "y" is greater than 0

        if (x > 0 && y > 0)

        {

            //return "1"

            return 1;

        }

/*check "x" is less than 0 and "y" is greater than 0*/

        else if (x < 0 && y > 0)

        {

            //return "2"

            return 2;

        }

        //check "x" and "y" is less than 0

        else if (x < 0 && y < 0)

        {

            //return "3"

            return 3;

        }

/*check "x" is greater than 0 and "y" is less than 0*/

        else if (x > 0 && y < 0)

        {

            //return "4"

            return 4;

        }

        //otherwise

        else

        {

            //return "0"

            return 0;

        }

    }

}

Explanation:

• In the above program, the “Point” is the class name,
• Inside the “Point” class, declare the “x” and “y” variables and the accessor method, the “quadrant” is the method name
  • If the “x” and “y” are greater than 0, then return 1 to the called method.
  • If the “x” is less than 0 and “y” is greater than 0, then return 2 to the called method.
  • If the “x” and “y” are less than 0, then return 3 to the called method.
  • If the “x” is greater than 0 and “y” is less than 0, then return 4 to the called method.