Chapter 8, Problem 26P

### College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300

Chapter
Section

### College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300
Textbook Problem

# A window washer is standing on a scaffold supported by a vertical rope at each end. The scaffold weighs 200 N and is 3.00 in long. What is the tension in each rope when the 700-N worker stands 1.00 m from one end?

To determine
The tension in each rope when the worker stands 1.00m from one end.

Explanation

Given info: The weight of the washer is 700â€‰N , weight of the scaffold is 200â€‰N , length of the scaffold is 3.00â€‰m , distance of the washer from the left end is 1.00â€‰m and the tension in the right side of the cable is 333â€‰N .

Explanation: At rotational equilibrium, the sum of torques on system is âˆ‘Ï„=0=LT2âˆ’(L/2)Wsâˆ’L1Ww and the torque due to the tension T1 is zero hence it is at the pivot.

The formula for the tension in the right side of the cable is,

T2=Ws2+L1LWw

• Ws is weight of the scaffold.
• Ww is weight of the washer.
• L1 is the distance of the washer from the left end.
• L is length of the scaffold.

Substitute 700â€‰N for Ww , 200â€‰N for Ws , 3.00â€‰m for L , and 1.00â€‰m for L1 to find T2 .

T2=200â€‰N2+(1

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