   Chapter 8, Problem 26P

Chapter
Section
Textbook Problem

A window washer is standing on a scaffold supported by a vertical rope at each end. The scaffold weighs 200 N and is 3.00 in long. What is the tension in each rope when the 700-N worker stands 1.00 m from one end?

To determine
The tension in each rope when the worker stands 1.00m from one end.

Explanation

Given info: The weight of the washer is 700N , weight of the scaffold is 200N , length of the scaffold is 3.00m , distance of the washer from the left end is 1.00m and the tension in the right side of the cable is 333N .

Explanation: At rotational equilibrium, the sum of torques on system is τ=0=LT2(L/2)WsL1Ww and the torque due to the tension T1 is zero hence it is at the pivot.

The formula for the tension in the right side of the cable is,

T2=Ws2+L1LWw

• Ws is weight of the scaffold.
• Ww is weight of the washer.
• L1 is the distance of the washer from the left end.
• L is length of the scaffold.

Substitute 700N for Ww , 200N for Ws , 3.00m for L , and 1.00m for L1 to find T2 .

T2=200N2+(1

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