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Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692

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Section
BuyFindarrow_forward

Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692
Chapter 8, Problem 32E
Textbook Problem
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Write nuclear equations to represent each process:

alpha decay of Rn-220

beta decay of Bi-212

alpha decay of Ra-224

beta decay of Tl-208

Interpretation Introduction

Interpretation:

The balanced nuclear equation for each of the given processes is to be represented.

Concept Introduction:

There is a difference between a chemical reaction and a nuclear reaction. A chemical reaction involves atoms, molecules and electrons whereas a nuclear reaction involves the nucleus of an atom.

Explanation of Solution

a) Alpha decay of Rn220

In a nuclear equation, each element is represented by its appropriate chemical symbol. There are two numbers written along with the chemical symbol. One is the mass number, which is written on the upper side and the other is the atomic number, which is written on the lower side. The mass number is denoted by A and the atomic number is denoted by Z.

In a balanced nuclear equation, the sum of atomic number and mass number is the same on both sides of the nuclear equation.

The balanced nuclear equation for the alpha decay of Rn220 is represented as follows:

86220Rn84216Po+24He

In this equation, the sum of atomic numbers is the same on both sides, that is, 86 and the sum of mass numbers is also the same on both sides, that is, 220.

b) Beta decay of Bi212

In a balanced nuclear equation, the sum of mass number and atomic number is the same on both sides of the equation.

The balanced nuclear equation for the beta decay of Bi212 is represented as follows:

83212Bi84212Po+10e

In this equation, the sum of atomic numbers is the same on both sides, that is, 83 and the sum of mass numbers is also the same on both sides, that is, 212

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Chapter 8 Solutions

Chemistry In Focus
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