   Chapter 8, Problem 38P

Chapter
Section
Textbook Problem

If the system shown in  Figure P8.37 is set in rotation about each of the axes mentioned in Problem 37, find the torque that will produce an angular acceleration of 1.50 rad/s2 in each case.Figure P8.37 Problems 37 and 38.

To determine
Torques of these objects about x , y axes, and the point O .

Explanation

Section1:

To determine: The torque of these objects about x-axis.

Answer: The torque of these objects about x -axis is 149Nm .

Explanation:

Given info: The angular acceleration of these objects is 1.50rad/s2 and the moment of inertia of the objects about x -axis is 99.0kg/m2 .

The formula for the torque about x- axis is,

τx=Ixα

• τx is the torque about x- axis
• Ix is moment of inertia about x- axis
• α is angular acceleration of the object

Substitute 99.0kg/m2 for Ix and 1.50rad/s2 for α to find τx .

Thus the torque about x- axis is 149Nm .

Section 2:

To determine: The torque of these objects about y -axis.

Answer: The torque of these objects about y -axis is 66.0Nm .

Explanation:

Given info: The angular acceleration of these objects is 1.50rad/s2 and the moment of inertia of the objects about y -axis is 44.0kgm2 .

τy=Iyα

• τy is moment of inertia about y -axis
• Iy is the moment of inertia  about y axis

Substitute 44.0kgm2 for Ix and 1

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