Chapter 8, Problem 48P

### College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300

Chapter
Section

### College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300
Textbook Problem

# A 2.50-kg solid, uniform disk rolls without slipping across a level surface, translating at 3.75 m/s. If the disk’s radius is 0.100 m, find its (a) translational kinetic energy and (b) rotational kinetic energy.

(a)

To determine
The translational kinetic energy of the solid uniform disk.

Explanation

Given info: The mass of the disk is 2.50â€‰kg and the translational velocity of the disk is 3.75â€‰m/s .

Explanation:

The formula for the translational kinetic energy of the solid uniform disk,

KEt=12mv2

• m is mass of the disk.
• v is translational velocity of the disk.

Substitute 2.50â€‰kg for m and 3.75â€‰m/s for v to find KEt

(b)

To determine
The rotational kinetic energy of the disk.

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