(a) Interpretation: The number of moles and mass of positive ions present in the sample should be calculated. Concept Introduction: Number of moles is related to mass and molar mass as follows: n = m M Here, m is mass and M is molar mass. According to Avogadro’s law, 1 mole of a substance contains 6.023 × 10 23 atoms. This is known as Avogadro’s number and denoted by symbol N A . Thus, number of molecules can be calculated from number of moles using the following conversion factor: ( 6.023 × 10 23 molecules 1 mol ) .

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Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781337399425
BuyFind

Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781337399425

Solutions

Chapter 8, Problem 51QAP
Interpretation Introduction

(a)

Interpretation:

The number of moles and mass of positive ions present in the sample should be calculated.

Concept Introduction:

Number of moles is related to mass and molar mass as follows:

n=mM

Here, m is mass and M is molar mass.

According to Avogadro’s law, 1 mole of a substance contains6.023×1023 atoms. This is known as Avogadro’s number and denoted by symbolNA.

Thus, number of molecules can be calculated from number of moles using the following conversion factor:

(6.023×1023 molecules1 mol).

Interpretation Introduction

(a)

Interpretation:

The number of moles and mass of positive ions present in the sample should be calculated.

Concept Introduction:

Number of moles is related to mass and molar mass as follows:

n=mM

Here, m is mass and M is molar mass.

According to Avogadro’s law, 1 mole of a substance contains6.023×1023 atoms. This is known as Avogadro’s number and denoted by symbolNA.

Thus, number of molecules can be calculated from number of moles using the following conversion factor:

(6.023×1023 molecules1 mol)

Number of moles and mass of ammonium ion is 12.64 mol and 228 g respectively.

Number of moles of ammonium sulfide(NH4)2S is 6.31 mol

From the formula, 1 mol of(NH4)2S contains 2 mol ofNH4+ that is positive ion in(NH4)2S. Thus, number of moles ofNH4+ in 6.31 mol of(NH4)2S is2×6.31 mol=12.62 mol

From number of moles, mass can be calculated as follows:

m=n×M

Molar mass of ammonium ion is 18.04 g/mol.

Putting the values,

m=12.64 mol×18.04 g/mol=228 g

Therefore, number of moles and mass of ammonium ion is 12.64 mol and 228 g respectively.

(c)

Interpretation:

The number of moles and mass of positive ions present in the sample should be calculated.

Concept Introduction:

Number of moles is related to mass and molar mass as follows:

n=mM

Here, m is mass and M is molar mass.

According to Avogadro’s law, 1 mole of a substance contains6.023×1023 atoms. This is known as Avogadro’s number and denoted by symbolNA.

Thus, number of molecules can be calculated from number of moles using the following conversion factor:

(6.023×1023 molecules1 mol).

Number of moles and mass of barium ion is 0.0606 mol and 8.322 g respectively.

Mass of barium phosphideBa3P2 is 9.71 g

From mass, number of moles can be calculated as follows:

n=mM

Molar mass ofBa3P2 is 479.977 g/mol thus, number of moles will be:

n=9.71 g479.977 g/mol=0.0202 mol

Thus, number of moles ofBa3P2 is 0.0202 mol.

From the formula, 1 mol ofBa3P2 contains 3 mol ofBa2+ that is positive ion inBa3P2. Thus, number of moles ofBa2+ in 0.0202 mol ofBa3P2 is3×0.0202 mol=0.0606 mol

From number of moles, mass can be calculated as follows:

m=n×M

Molar mass of barium ion is 137.327 g/mol.

Putting the values,

m=0.0606 mol×137.327 g/mol=8.322 g

Therefore, number of moles and mass of barium ion is 0.0606 mol and 8.322 g respectively.

(d)

Interpretation:

The number of moles and mass of positive ions present in the sample should be calculated.

Concept Introduction:

Number of moles is related to mass and molar mass as follows:

n=mM

Here, m is mass and M is molar mass.

According to Avogadro’s law, 1 mole of a substance contains6.023×1023 atoms. This is known as Avogadro’s number and denoted by symbolNA.

Thus, number of molecules can be calculated from number of moles using the following conversion factor:

(6.023×1023 molecules1 mol).

Number of moles and mass of calcium ion is 22.89 mol and917.385 g respectively.

Number of moles of calcium phosphateCa3(PO4)2 is 7.63 mol

From the formula, 1 mol ofCa3(PO4)2 contains 3 mol ofCa2+ that is positive ion inCa3(PO4)2. Thus, number of moles ofCa2+ in 7.63 mol ofCa3(PO4)2 is3×7.63 mol=22.89 mol

From number of moles, mass can be calculated as follows:

m=n×M

Molar mass of calcium ion is 40.078 g/mol.

Putting the values,

m=22.89 mol×40.078 g/mol=917.385 g

Therefore, number of moles and mass of calcium ion is 22.89 mol and917.385 g respectively.

Interpretation Introduction

(c)

Interpretation:

The number of moles and mass of positive ions present in the sample should be calculated.

Concept Introduction:

Number of moles is related to mass and molar mass as follows:

n=mM

Here, m is mass and M is molar mass.

According to Avogadro’s law, 1 mole of a substance contains6.023×1023 atoms. This is known as Avogadro’s number and denoted by symbolNA.

Thus, number of molecules can be calculated from number of moles using the following conversion factor:

(6.023×1023 molecules1 mol).

Interpretation Introduction

(d)

Interpretation:

The number of moles and mass of positive ions present in the sample should be calculated.

Concept Introduction:

Number of moles is related to mass and molar mass as follows:

n=mM

Here, m is mass and M is molar mass.

According to Avogadro’s law, 1 mole of a substance contains6.023×1023 atoms. This is known as Avogadro’s number and denoted by symbolNA.

Thus, number of molecules can be calculated from number of moles using the following conversion factor:

(6.023×1023 molecules1 mol).

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