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For each of the following samples of ionic substances, calculate the number of moles and mass of the positive ions present in each sample. l type="a"> 4.25 g of ammonium iodide, NH 4 I i>6.31 moles of ammonium sulfide, ( NH 4 ) 2 S i>9.71 g of barium phosphide, Ba 3 P 2 i>7.63 moles of calcium phosphate, Ca 3 ( PO 4 ) 2

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Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781337399425

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BuyFindarrow_forward

Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781337399425
Chapter 8, Problem 51QAP
Textbook Problem
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For each of the following samples of ionic substances, calculate the number of moles and mass of the positive ions present in each sample.

l type="a">

  • 4.25 g of ammonium iodide, NH 4 I
  • i>6.31 moles of ammonium sulfide, ( NH 4 ) 2 S

    i>9.71 g of barium phosphide, Ba 3 P 2

    i>7.63 moles of calcium phosphate, Ca 3 ( PO 4 ) 2

    Interpretation Introduction

    (a)

    Interpretation:

    The number of moles and mass of positive ions present in the sample should be calculated.

    Concept Introduction:

    Number of moles is related to mass and molar mass as follows:

    n=mM

    Here, m is mass and M is molar mass.

    According to Avogadro’s law, 1 mole of a substance contains6.023×1023 atoms. This is known as Avogadro’s number and denoted by symbolNA.

    Thus, number of molecules can be calculated from number of moles using the following conversion factor:

    (6.023×1023 molecules1 mol).

    Explanation of Solution

    The mass of ammonium iodideNH4I is 4.25 g.

    From mass, number of moles can be calculated as follows:

    n=mM

    Molar mass ofNH4I is 144.94 g/mol thus, number of moles will be:

    n=4.25 g144.94 g/mol=0.03 mol

    Thus, number of moles ofNH4I is 0.03 mol

    Interpretation Introduction

    (a)

    Interpretation:

    The number of moles and mass of positive ions present in the sample should be calculated.

    Concept Introduction:

    Number of moles is related to mass and molar mass as follows:

    n=mM

    Here, m is mass and M is molar mass.

    According to Avogadro’s law, 1 mole of a substance contains6.023×1023 atoms. This is known as Avogadro’s number and denoted by symbolNA.

    Thus, number of molecules can be calculated from number of moles using the following conversion factor:

    (6.023×1023 molecules1 mol)

    Number of moles and mass of ammonium ion is 12.64 mol and 228 g respectively.

    Number of moles of ammonium sulfide(NH4)2S is 6.31 mol

    From the formula, 1 mol of(NH4)2S contains 2 mol ofNH4+ that is positive ion in(NH4)2S. Thus, number of moles ofNH4+ in 6.31 mol of(NH4)2S is2×6.31 mol=12.62 mol

    From number of moles, mass can be calculated as follows:

    m=n×M

    Molar mass of ammonium ion is 18.04 g/mol.

    Putting the values,

    m=12.64 mol×18.04 g/mol=228 g

    Therefore, number of moles and mass of ammonium ion is 12.64 mol and 228 g respectively.

    (c)

    Interpretation:

    The number of moles and mass of positive ions present in the sample should be calculated.

    Concept Introduction:

    Number of moles is related to mass and molar mass as follows:

    n=mM

    Here, m is mass and M is molar mass.

    According to Avogadro’s law, 1 mole of a substance contains6.023×1023 atoms. This is known as Avogadro’s number and denoted by symbolNA.

    Thus, number of molecules can be calculated from number of moles using the following conversion factor:

    (6.023×1023 molecules1 mol).

    Number of moles and mass of barium ion is 0.0606 mol and 8.322 g respectively.

    Mass of barium phosphideBa3P2 is 9.71 g

    From mass, number of moles can be calculated as follows:

    n=mM

    Molar mass ofBa3P2 is 479.977 g/mol thus, number of moles will be:

    n=9.71 g479.977 g/mol=0.0202 mol

    Thus, number of moles ofBa3P2 is 0.0202 mol.

    From the formula, 1 mol ofBa3P2 contains 3 mol ofBa2+ that is positive ion inBa3P2. Thus, number of moles ofBa2+ in 0.0202 mol ofBa3P2 is3×0.0202 mol=0.0606 mol

    From number of moles, mass can be calculated as follows:

    m=n×M

    Molar mass of barium ion is 137.327 g/mol.

    Putting the values,

    m=0.0606 mol×137.327 g/mol=8.322 g

    Therefore, number of moles and mass of barium ion is 0.0606 mol and 8.322 g respectively.

    (d)

    Interpretation:

    The number of moles and mass of positive ions present in the sample should be calculated.

    Concept Introduction:

    Number of moles is related to mass and molar mass as follows:

    n=mM

    Here, m is mass and M is molar mass.

    According to Avogadro’s law, 1 mole of a substance contains6.023×1023 atoms. This is known as Avogadro’s number and denoted by symbolNA.

    Thus, number of molecules can be calculated from number of moles using the following conversion factor:

    (6.023×1023 molecules1 mol).

    Number of moles and mass of calcium ion is 22.89 mol and917.385 g respectively.

    Number of moles of calcium phosphateCa3(PO4)2 is 7.63 mol

    From the formula, 1 mol ofCa3(PO4)2 contains 3 mol ofCa2+ that is positive ion inCa3(PO4)2. Thus, number of moles ofCa2+ in 7.63 mol ofCa3(PO4)2 is3×7.63 mol=22.89 mol

    From number of moles, mass can be calculated as follows:

    m=n×M

    Molar mass of calcium ion is 40.078 g/mol.

    Putting the values,

    m=22.89 mol×40.078 g/mol=917.385 g

    Therefore, number of moles and mass of calcium ion is 22.89 mol and917.385 g respectively.

    Interpretation Introduction

    (c)

    Interpretation:

    The number of moles and mass of positive ions present in the sample should be calculated.

    Concept Introduction:

    Number of moles is related to mass and molar mass as follows:

    n=mM

    Here, m is mass and M is molar mass.

    According to Avogadro’s law, 1 mole of a substance contains6.023×1023 atoms. This is known as Avogadro’s number and denoted by symbolNA.

    Thus, number of molecules can be calculated from number of moles using the following conversion factor:

    (6.023×1023 molecules1 mol).

    Interpretation Introduction

    (d)

    Interpretation:

    The number of moles and mass of positive ions present in the sample should be calculated.

    Concept Introduction:

    Number of moles is related to mass and molar mass as follows:

    n=mM

    Here, m is mass and M is molar mass.

    According to Avogadro’s law, 1 mole of a substance contains6.023×1023 atoms. This is known as Avogadro’s number and denoted by symbolNA.

    Thus, number of molecules can be calculated from number of moles using the following conversion factor:

    (6.023×1023 molecules1 mol).

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