Which of the following compounds or ions do not have an octet of electrons surrounding the central atom: BF 4 − , SiF 4 , SeF 4 , BrF 4 − , XeF 4 ?

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Interpretation Introduction Interpretation: The compounds or ions that do not have octet of electrons around central atoms should be identified. Concept Introduction: Octet rule: The atoms of main group element tend to combine with other atoms in such a way that each atom has eight electrons in its valence shell, giving it the electron configuration same as a Nobel gas. Explanation Reasons for correct answers: The Lewis electron dot structure for given molecules are determined by first drawing the skeletal structure for the given molecules, then the total number of valence electrons for all atoms present in the molecules are determined. The next step is to subtract the electrons present in the total number of bonds present in the skeletal structure of the molecule with the total valence electrons such that considering each bond contains two electrons with it. Finally, the electrons which got after subtractions have to be equally distributed considering each atom contains eight electrons in its valence shell. The Lewis structure for SeF 4 , BrF 4 − and XeF 4 shows the electrons surrounding the central atom as follows, The above Lewis structure clearly shows that the central atom in SeF 4 , BrF 4 − and XeF 4 do not contain octet of electrons

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Answer 1

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Chemistry & Chemical Reactivity

9th Edition

John C. Kotz + 3 others

Publisher: Cengage Learning

ISBN: 9781133949640

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BuyFind

Chemistry & Chemical Reactivity

9th Edition

John C. Kotz + 3 others

Publisher: Cengage Learning

ISBN: 9781133949640

Solutions

Chapter

Section

Answer 3

Solutions

Chapter

Section

Answer 4

Chapter

Section

Answer 5

Interpretation Introduction

Interpretation: The compounds or ions that do not have octet of electrons around central atoms should be identified.

Concept Introduction:

Octet rule: The atoms of main group element tend to combine with other atoms in such a way that each atom has eight electrons in its valence shell, giving it the electron configuration same as a Nobel gas.

Explanation of Solution

Reasons for correct answers:

The Lewis electron dot structure for given molecules are determined by first drawing the skeletal structure for the given molecules, then the total number of valence electrons for all atoms present in the molecules are determined.

The next step is to subtract the electrons present in the total number of bonds present in the skeletal structure of the molecule with the total valence electrons such that considering each bond contains two electrons with it.

Finally, the electrons which got after subtractions have to be equally distributed considering each atom contains eight electrons in its valence shell.

The Lewis structure for SeF4, BrF4− and XeF4 shows the electrons surrounding the central atom as follows,

The above Lewis structure clearly shows that the central atom in SeF4, BrF4− and XeF4 do not contain octet of electrons

Which of the following compounds or ions do not have an octet of electrons surrounding the central atom: BF 4 − , SiF 4 , SeF 4 , BrF 4 − , XeF 4 ?

Chemistry & Chemical Reactivity

Solutions

Chemistry & Chemical Reactivity

Which of the following compounds or ions do not have an octet of electrons surrounding the central atom: BF₄⁻, SiF₄, SeF₄, BrF₄⁻, XeF₄?

Explanation of Solution

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Which of the following compounds or ions do not have an octet of electrons surrounding the central atom: BF 4 − , SiF 4 , SeF 4 , BrF 4 − , XeF 4 ?

Chemistry & Chemical Reactivity

Solutions

Chemistry & Chemical Reactivity