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College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300

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BuyFindarrow_forward

College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300
Textbook Problem

A light, rigid rod of length = 1.00 m rotates about an axis perpendicular to its length and through its center, as shown in Figure P8.51. Two particles of masses m1 = 4.00 kg and m2 = 3.00 kg are connected to the ends of the rod. What is the angular momentum of the system if the speed of each particle is 5.00 m/s? (Neglect the rod’s mass.)

To determine
The angular momentum of the system if the speed of each particle is 5.00m/s .

Explanation

Given info: The translational speed of each particle is 5.00m/s location of these particles from center of the rod is 1.00m/2 , and masses of each particles are 4.00kg and 3.00kg .

Explanation: The moment of inertia of the system by omitting the mass of the rod is I=m1r2+m2r2 and then its angular speed would be related to the translational speed as ω=v/r . By using these expressions, the angular momentum L=Iω of the system would be calculated.

The formula for the angular momentum of the system is,

L=(m1r2+m2r2)vr

  • m1 and m2 are particles masses
  • r is location of the particle from center of the rod.
  • v is translational speed of these particles.

Substitute 4

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