   Chapter 8, Problem 65P

Chapter
Section
Textbook Problem

A light, rigid rod of length ℓ = 1.00 m rotates about an axis perpendicular to its length and through its center, as shown in Figure P8.51. Two particles of masses m1 = 4.00 kg and m2 = 3.00 kg are connected to the ends of the rod. What is the angular momentum of the system if the speed of each particle is 5.00 m/s? (Neglect the rod’s mass.)

To determine
The angular momentum of the system if the speed of each particle is 5.00m/s .

Explanation

Given info: The translational speed of each particle is 5.00m/s location of these particles from center of the rod is 1.00m/2 , and masses of each particles are 4.00kg and 3.00kg .

Explanation: The moment of inertia of the system by omitting the mass of the rod is I=m1r2+m2r2 and then its angular speed would be related to the translational speed as ω=v/r . By using these expressions, the angular momentum L=Iω of the system would be calculated.

The formula for the angular momentum of the system is,

L=(m1r2+m2r2)vr

• m1 and m2 are particles masses
• r is location of the particle from center of the rod.
• v is translational speed of these particles.

Substitute 4

Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

A deficiency of niacin may result in which disease? pellagra beriberi scurvy rickets

Nutrition: Concepts and Controversies - Standalone book (MindTap Course List)

What is physically exchanged during crossing over?

Human Heredity: Principles and Issues (MindTap Course List)

What is an enzyme turnover number?

General, Organic, and Biological Chemistry 