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Hydrogen cyanide is prepared commercially by the reaction of methane, CH 4 ( g ), ammonia, NH 3 (g), and oxygen, O 2 (g), at high temperature. The other product is gaseous water. a. Write a chemical equation for the reaction. b. What volume of HCN( g ) can be obtained from the reaction of 20.0 L CH 4 ( g ), 20.0 L NH 3 ( g ), and 20.0 L O 2 ( g )? The volumes of all gases are measured at the same temperature and pressure.

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Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

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Chapter
Section
BuyFindarrow_forward

Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 8, Problem 75E
Textbook Problem
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Hydrogen cyanide is prepared commercially by the reaction of methane, CH4(g), ammonia, NH3(g), and oxygen, O2(g), at high temperature. The other product is gaseous water.

a. Write a chemical equation for the reaction.

b. What volume of HCN(g) can be obtained from the reaction of 20.0 L CH4(g), 20.0 L NH3(g), and 20.0 L O2(g)? The volumes of all gases are measured at the same temperature and pressure.

a)

Interpretation Introduction

Interpretation: The chemical equation for HCN formed in the given reaction of CH4 , NH3 and O2 should be determined. If 20L of reactants are used.

Concept introduction:

  • The chemical equation for a reaction is the representation of reaction with an arrow in which reactants are in the left side and products are in the right side of arrow.
  • Balance equation is the chemical equation of a reaction which is written according to law of conservation of mass.
  • Limiting reagent: limiting reagent is a reactant, which consumes completely in the chemical reaction. The quantity of the product depends on this limiting reagent, it can be determined with the help of balanced chemical equation for the reaction.
  • According toAvogadro’s law: the volume of gas is directly proportional to the number of moles of gas at constant pressure and temperature.

    Equation of Avogadro’s law for two gases (1 and two) at constant P and T,

  • V1n1=V2n2V1V2=n1n2

To determine: The chemical equation for HCN formed in the given reaction of CH4 , NH3 and O2 should be determined. If 20L of reactants are used.

Explanation of Solution

In the given reaction HCN is formed by the reaction of CH4 , NH3 and O2 .

The chemical equation for a reaction is the representation of reaction with an arrow in which reactants are in the left side and products are in the right side of arrow.

Therefore,

The given reaction can be written as,

CH4(g)+NH3(g)+O2(g)HCN(g)+

b)

Interpretation Introduction

Interpretation: The volume of HCN formed in the given reaction of CH4 , NH3 and O2 should be determined. If 20L of reactants are used.

Concept introduction:

  • The chemical equation for a reaction is the representation of reaction with an arrow in which reactants are in the left side and products are in the right side of arrow.
  • Balance equation is the chemical equation of a reaction which is written according to law of conservation of mass.
  • Limiting reagent: limiting reagent is a reactant, which consumes completely in the chemical reaction. The quantity of the product depends on this limiting reagent, it can be determined with the help of balanced chemical equation for the reaction.
  • According toAvogadro’s law: the volume of gas is directly proportional to the number of moles of gas at constant pressure and temperature.

    Equation of Avogadro’s law for two gases (1 and two) at constant P and T,

  • V1n1=V2n2V1V2=n1n2

To determine: The volume of HCN formed in the given reaction of CH4 , NH3 and O2 should be determined. If 20L of reactants are used

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Chapter 8 Solutions

Chemistry: An Atoms First Approach
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