Modified Masteringchemistry With Pearson Etext -- Valuepack Access Card -- For Fundamentals Of General, Organic, And Biological Chemistry
Modified Masteringchemistry With Pearson Etext -- Valuepack Access Card -- For Fundamentals Of General, Organic, And Biological Chemistry
8th Edition
ISBN: 9780134261270
Author: John E.; Ballantine, David S.; Hoeger, Carl A.; Peterson, Virginia E. Mcmurry
Publisher: Prentice Hall
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Concept explainers

Question
Chapter 8, Problem 8.26UKC

(a)

Interpretation Introduction

Interpretation:

The apparatus has to be redrawn if the temperature is increased from 300Kto450K at constant pressure.

Concept introduction:

Charles’s law: States that volume is directly proportional to temperature when the gas is held at constant pressure and number of molecules.

VTV=Constant×TV1T1=V2T2

(a)

Expert Solution
Check Mark

Answer to Problem 8.26UKC

According to Charles’s law, if temperature increases at constant pressure, then volume also increases. Therefore, the apparatus is redrawn as given below:

Modified Masteringchemistry With Pearson Etext -- Valuepack Access Card -- For Fundamentals Of General, Organic, And Biological Chemistry, Chapter 8, Problem 8.26UKC , additional homework tip  1

Explanation of Solution

Given data is that the temperature increases from 300Kto450K at constant pressure.

Charles’s law is the gas law which relates volume and temperature at constant pressure and number of molecules.

From Charles’s law we know that V1T1=V2T2

According to Charles’s law, if temperature increases at constant pressure, then volume also increases. Therefore, the apparatus is redrawn as given below:

Modified Masteringchemistry With Pearson Etext -- Valuepack Access Card -- For Fundamentals Of General, Organic, And Biological Chemistry, Chapter 8, Problem 8.26UKC , additional homework tip  2

(b)

Interpretation Introduction

Interpretation:

The apparatus has to be redrawn if the pressure is increased from 1atmto2atm at constant temperature.

Concept introduction:

Boyle’s law:

At fixed temperature, the volume of a fixed amount of gas is inversely proportional to the pressure exerted by the gas.

P1V(n,Twillbeconstant)PV=constantP1V1=P2V2

(b)

Expert Solution
Check Mark

Answer to Problem 8.26UKC

According to Boyle’s law, if pressure increases at constant temperature, then volume decreases. Therefore, the apparatus is redrawn as given below:

Modified Masteringchemistry With Pearson Etext -- Valuepack Access Card -- For Fundamentals Of General, Organic, And Biological Chemistry, Chapter 8, Problem 8.26UKC , additional homework tip  3

Explanation of Solution

Given data is that the pressure is increased from 1atmto2atm at constant temperature

Boyle’s law is the law which relates pressure and volume at a constant temperature and number of molecules.

From Boyle’s law:

P1V1=P2V2

According to Boyle’s law, if pressure increases at constant temperature, then volume decreases. Therefore, the apparatus is redrawn as given below:

Modified Masteringchemistry With Pearson Etext -- Valuepack Access Card -- For Fundamentals Of General, Organic, And Biological Chemistry, Chapter 8, Problem 8.26UKC , additional homework tip  4

(c)

Interpretation Introduction

Interpretation:

The apparatus has to be redrawn if the temperature is decreased from 300Kto200K and the pressure is decreased from 3atmto2atm.

Concept introduction:

General Gas Law:

Combining Charles’s law and Boyle’s law we get the General gas law or combined gas law.

P1V1T1=P2V2T2

(c)

Expert Solution
Check Mark

Answer to Problem 8.26UKC

The volume remains unchanged and the apparatus is redrawn as given below:

Modified Masteringchemistry With Pearson Etext -- Valuepack Access Card -- For Fundamentals Of General, Organic, And Biological Chemistry, Chapter 8, Problem 8.26UKC , additional homework tip  5

Explanation of Solution

Given data is that the temperature is decreased from 300Kto200K and the pressure is decreased from 3atmto2atm.

P1=3atmT1=300KT2=200KP2=2atm

Combined gas law is proposed by combining the Boyle’s law and Charle’s law and is given by:

P1V1T1=P2V2T2

P1V1T1=P2V2T23atmV1300K=2atmV2200KV1V2=1

Therefore, the volume remains unchanged and the apparatus is redrawn as given below:

Modified Masteringchemistry With Pearson Etext -- Valuepack Access Card -- For Fundamentals Of General, Organic, And Biological Chemistry, Chapter 8, Problem 8.26UKC , additional homework tip  6

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Chapter 8 Solutions

Modified Masteringchemistry With Pearson Etext -- Valuepack Access Card -- For Fundamentals Of General, Organic, And Biological Chemistry

Ch. 8.5 - Prob. 8.4CIAPCh. 8.5 - Prob. 8.5CIAPCh. 8.5 - Prob. 8.9PCh. 8.5 - Prob. 8.10PCh. 8.6 - Prob. 8.11PCh. 8.7 - Prob. 8.12PCh. 8.8 - Prob. 8.13PCh. 8.8 - Prob. 8.14KCPCh. 8.9 - Prob. 8.15PCh. 8.10 - Prob. 8.16PCh. 8.10 - Prob. 8.17PCh. 8.10 - Prob. 8.18KCPCh. 8.11 - Prob. 8.19PCh. 8.11 - Prob. 8.20PCh. 8.11 - Prob. 8.21PCh. 8.11 - Prob. 8.22KCPCh. 8.14 - How much heat in kilocalories is required to (a)...Ch. 8.14 - Prob. 8.24PCh. 8.14 - Compare the Hvap values for water, isopropyl...Ch. 8.14 - What is a supercritical fluid?Ch. 8.14 - What are the environmental advantages of using...Ch. 8.14 - Prob. 8.8CIAPCh. 8 - Prob. 8.26UKCCh. 8 - Assume that you have a sample of gas at 350 K in a...Ch. 8 - Prob. 8.28UKCCh. 8 - Three bulbs, two of which contain different gases...Ch. 8 - Prob. 8.30UKCCh. 8 - The following graph represents the heating curve...Ch. 8 - Prob. 8.32UKCCh. 8 - Prob. 8.33UKCCh. 8 - Prob. 8.34APCh. 8 - Identify the predominant intermolecular force in...Ch. 8 - Dimethyl ether (CH3OCH3) and ethanol (C2H5OH) have...Ch. 8 - Prob. 8.37APCh. 8 - Prob. 8.38APCh. 8 - Prob. 8.39APCh. 8 - What are the four assumptions of the...Ch. 8 - Prob. 8.41APCh. 8 - Prob. 8.42APCh. 8 - Prob. 8.43APCh. 8 - Prob. 8.44APCh. 8 - Prob. 8.45APCh. 8 - Prob. 8.46APCh. 8 - Which assumptions of the kinetic-molecular theory...Ch. 8 - Prob. 8.48APCh. 8 - Prob. 8.49APCh. 8 - The use of CFCs as refrigerants and propellants in...Ch. 8 - Prob. 8.51APCh. 8 - Prob. 8.52APCh. 8 - Prob. 8.53APCh. 8 - Prob. 8.54APCh. 8 - Prob. 8.55APCh. 8 - Prob. 8.56APCh. 8 - Prob. 8.57APCh. 8 - Prob. 8.58APCh. 8 - Which assumptions of the kinetic-molecular theory...Ch. 8 - Prob. 8.60APCh. 8 - Prob. 8.61APCh. 8 - Prob. 8.62APCh. 8 - Prob. 8.63APCh. 8 - Prob. 8.64APCh. 8 - Prob. 8.65APCh. 8 - Prob. 8.66APCh. 8 - Prob. 8.67APCh. 8 - Prob. 8.68APCh. 8 - Prob. 8.69APCh. 8 - Prob. 8.70APCh. 8 - Prob. 8.71APCh. 8 - What is the mass of CH4 in a sample that occupies...Ch. 8 - Prob. 8.73APCh. 8 - Prob. 8.74APCh. 8 - Prob. 8.75APCh. 8 - Prob. 8.76APCh. 8 - Prob. 8.77APCh. 8 - Prob. 8.78APCh. 8 - Prob. 8.79APCh. 8 - Prob. 8.80APCh. 8 - Prob. 8.81APCh. 8 - Prob. 8.82APCh. 8 - Prob. 8.83APCh. 8 - Prob. 8.84APCh. 8 - Prob. 8.85APCh. 8 - Prob. 8.86APCh. 8 - Prob. 8.87APCh. 8 - Prob. 8.88APCh. 8 - Prob. 8.89APCh. 8 - Prob. 8.90APCh. 8 - Prob. 8.91APCh. 8 - Prob. 8.92APCh. 8 - Prob. 8.93APCh. 8 - Prob. 8.94APCh. 8 - Patients with a high body temperature are often...Ch. 8 - Prob. 8.96APCh. 8 - List three kinds of crystalline solids, and give...Ch. 8 - The heat of fusion of acetic acid, the principal...Ch. 8 - Prob. 8.99APCh. 8 - Prob. 8.100CPCh. 8 - Prob. 8.101CPCh. 8 - Prob. 8.102CPCh. 8 - Prob. 8.103CPCh. 8 - Prob. 8.104CPCh. 8 - Prob. 8.105CPCh. 8 - Prob. 8.106CPCh. 8 - Prob. 8.107CPCh. 8 - Prob. 8.108CPCh. 8 - Ethylene glycol, C2H6O2, has one OH bonded to each...Ch. 8 - Prob. 8.110CPCh. 8 - Prob. 8.111GPCh. 8 - Prob. 8.112GPCh. 8 - Prob. 8.113GPCh. 8 - Prob. 8.114GPCh. 8 - Prob. 8.115GP
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