Chapter 8, Problem 8.75EP

(a)

Interpretation Introduction

Interpretation:

The concentration of hydrogen peroxide has to be calculated if $\text{70}\text{mL}$ of $\text{2}\text{.0}\text{\%}\text{(m/v)}$ hydrogen peroxide in water is diluted with $\text{50}\text{mL}$ of water.

Concept Introduction:

Mass–volume percent is given by,

    $\text{=}\frac{\text{Mass}\text{of}\text{solute}\text{in}\text{(g)}}{\text{Volume}\text{of}\text{solution}\text{(mL)}}\text{×}\text{100}$

(b)

Interpretation Introduction

Interpretation:

The concentration of hydrogen peroxide has to be calculated if $\text{70}\text{mL}$ of $\text{2}\text{.0}\text{\%}\text{(v/v)}$ hydrogen peroxide in water is diluted with $\text{50}\text{mL}$ of water.

Concept Introduction:

Volume–volume percent is given by,

    $\text{=}\frac{\text{Volume}\text{of}\text{solute}\text{(mL)}}{\text{Volume}\text{of}\text{solution}\text{(mL)}}\text{×}\text{100}$

(c)

Interpretation Introduction

Interpretation:

The concentration of hydrogen peroxide has to be calculated if $\text{70}\text{mL}$ of $\text{2}\text{.0}\text{\%}\text{(m/m)}$ hydrogen peroxide in water is diluted with $\text{50}\text{mL}$ of water.

Concept Introduction:

Mass-percent is given by,

    $\text{=}\frac{\text{Mass}\text{of}\text{solute}\text{in}\text{(g)}}{\text{Mass}\text{of}\text{solution}\text{(g)}}\text{×}\text{100}$

(d)

Interpretation Introduction

Interpretation:

The concentration of hydrogen peroxide has to be calculated if $\text{70}\text{mL}$ of $\text{2}\text{.0}\text{M}$ hydrogen peroxide in water is diluted with $\text{50}\text{mL}$ of water.

Concept Introduction:

Molarity:

Concentration of solution is given in the term of molarity it is given by,

    $\text{M}\text{=}\frac{\text{Moles}\text{of}\text{solute}}{\text{Liter}\text{of}\text{solution}}$