# Chapter 8, Problem 8.87QP

### Chemistry: Atoms First

3rd Edition
Julia Burdge + 1 other
ISBN: 9781259638138

Chapter
Section

### Chemistry: Atoms First

3rd Edition
Julia Burdge + 1 other
ISBN: 9781259638138

(a)

Interpretation Introduction

Interpretation: the price of K2SO4 (dollar per kilogram) to supply the same amount of potassium of KCl and the mass of K2O contains the same amount of potassium atoms in 1 kg of KCl are needed to be determined when KCl costs $0.55 per kilogram. Concept introduction: • Mass percentage of an element of a compound is the ratio of total mass of that element to the mass of whole compound and multiplied with hundred. • Equation for Number of moles of a substance, from its given mass is, Number of moles=GivenmassMolarmass • Number of grams of a substance from its number of moles is, Number of moles×Molecularmass in grams=Numberofgrams (b) Interpretation Introduction Interpretation: the price of K2SO4 (dollar per kilogram) to supply the same amount of potassium of KCl and the mass of K2O contains the same amount of potassium atoms in 1 kg of KCl are needed to be determined when KCl costs$0.55 per kilogram.

Concept introduction:

• Mass percentage of an element of a compound is the ratio of total mass of that element to the mass of whole compound and multiplied with hundred.
• Equation for Number of moles of a substance, from its given mass is,

Number of moles=GivenmassMolarmass

• Number of grams of a substance from its number of moles is,

Number of moles×Molecularmass in grams=Numberofgrams

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