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In the “Méthode Champenoise,” grape juice is fermented in a wine bottle to produce sparkling wine. The reaction is C 6 H 12 O 6 ( a q ) → 2C 2 H 5 OH ( a q ) + 2CO 2 ( g ) Fermentation of 750. mL grape juice (density = 1.0 g/cm 3 ) is allowed to take place in a bottle with a total volume of 825 mL until 12% by volume is ethanol (C 2 H 5 OH). Assuming that the CO 2 is insoluble in H 2 O (actually, a wrong assumption), what would be the pressure of CO 2 inside the wine bottle at 25°C? (The density of ethanol is 0.79 g/cm 3 .)

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Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

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BuyFindarrow_forward

Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 8, Problem 96E
Textbook Problem
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In the “Méthode Champenoise,” grape juice is fermented in a wine bottle to produce sparkling wine. The reaction is

C 6 H 12 O 6 ( a q )    2C 2 H 5 OH ( a q )   +  2CO 2 ( g )

Fermentation of 750. mL grape juice (density = 1.0 g/cm3) is allowed to take place in a bottle with a total volume of 825 mL until 12% by volume is ethanol (C2H5OH). Assuming that the CO2 is insoluble in H2O (actually, a wrong assumption), what would be the pressure of CO2 inside the wine bottle at 25°C? (The density of ethanol is 0.79 g/cm3.)

Interpretation Introduction

Interpretation:

The pressure of CO2 gas produced in the given fermentation reaction of grape juice is to be calculated if the volume of grape juice is 750mL and produced ethanol is 12% by volume in the given fermentation reaction.

Concept introduction:

  • Equation of mass of substance from its volume and density,
  •          Mass=Density×Volume
  • Number of moles of a substance from its given mass is,

    Number of moles=GivenmassMolecularmass

  • Mole ratios between the reactants of a reaction are depends upon the coefficients of respective reactant in a balanced chemical equation.
  • According to ideal gas equation for finding pressure of a gas,

Pressure=Numberofmoles×R×TemperatureVolume

Explanation of Solution

Explanation

  • To find: the volume of produced ethanol in the given reaction.

The volume of produced ethanol is 90L .

The volume of volume of grape juice is given as 750mL .

The volume of ethanol is given as 12% by volume of grape juice.

Therefore, the volume of ethanol is,

750mL×12100=90mL

Hence, the volume of produced ethanol is 90mL .

  • To find: the mass of produced ethanol from its volume in the given reaction.

The mass of produced ethanol is 71.1g .

The volume of produced ethanol is calculated as 90mL .

The density of ethanol is given as 0.79g/cm3

Equation for given mass from its volume and density,

  •        Mass=Density×Volume

Therefore,

The mass of produced ethanol is,

Mass=0.79gcm3×90mL×1cm31mL =71.1g

  • To find: the number of moles of ethanol is produced in the given reaction.

The number of moles of ethanol is produced is 1.5mol .

The mass of produced ethanol is calculated as 71.1g .

Number of moles of a substance from its given mass is,

Number of moles=GivenmassMolecularmass

The number of moles of ethanol is produced is,

Number of moles=71.1g46.07=1.5mol

Hence, the number of moles of ethanol is produced is 1.5mol .

  • To find: the number of moles of CO2 is produced in the given reaction.

The number of moles of CO2 is produced is 1.5mol .

The balanced equation of given reaction is,

C6H12O62C2H5OH+2CO2

The number of moles of C6H12O6 is fermented in the given reaction and 2 moles of ethanol and 2 moles of CO2

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Chapter 8 Solutions

Chemistry: An Atoms First Approach
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