   Chapter 8.1, Problem 14E ### Elementary Geometry for College St...

6th Edition
Daniel C. Alexander + 1 other
ISBN: 9781285195698

#### Solutions

Chapter
Section ### Elementary Geometry for College St...

6th Edition
Daniel C. Alexander + 1 other
ISBN: 9781285195698
Textbook Problem
1 views

# In Exercises 9 to 18, find the areas of the figures shown or described. ▱ E F G H

To determine

To find:

The area of EFGH

Explanation

1) Approach:

Area of the parallelogram is given by,

A=bh unit2.

Where b is the base of the length, h is the height.

2) Calculation:

Given,

In the parallelogram EFGH with side (s)=10 ft.

base (b)=(2+3)yd.

Let point I that lies on EF

Then HI¯ is the height of the parallelogram EFGH.

Find length of height (h):

For right triangle EIH,

Since, 1 yd=3 ft

EI=2 yd=6 ft

EH=10 ft

HI=h ft

By the Pythagorean theorem,

(EI)2+(HI)2=(EH)2

(6)2+(h)2

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