Chapter 8.1, Problem 14E

### Elementary Geometry For College St...

7th Edition
Alexander + 2 others
ISBN: 9781337614085

Chapter
Section

### Elementary Geometry For College St...

7th Edition
Alexander + 2 others
ISBN: 9781337614085
Textbook Problem

# In Exercises 9 to 18, find the areas of the figures shown or described. ▱ E F G H

To determine

To find:

The area of EFGH

Explanation

1) Approach:

Area of the parallelogram is given by,

A=bhÂ unit2.

Where b is the base of the length, h is the height.

2) Calculation:

Given,

In the parallelogram EFGH with side (s)=10Â ft.

baseÂ (b)=(2+3)yd.

Let point I that lies on EF

Then HIÂ¯ is the height of the parallelogram EFGH.

Find length of height (h):

For right triangle EIH,

Since, 1Â yd=3Â ft

EI=2Â yd=6Â ft

EH=10Â ft

HI=hÂ ft

By the Pythagorean theorem,

(EI)2+(HI)2=(EH)2

(6)2+(h)2

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