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Chapter 8.1, Problem 51E
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### Elementary Geometry For College St...

7th Edition
Alexander + 2 others
ISBN: 9781337614085

#### Solutions

Chapter
Section
BuyFindarrow_forward

### Elementary Geometry For College St...

7th Edition
Alexander + 2 others
ISBN: 9781337614085
Textbook Problem

# The area of a rectangle is 48  in 2 . Where x is the width and y is the length, express the perimeter P of the rectangle in terms only of x.

To determine

To find:

The perimeter P of the rectangle.

Explanation

Converting theoretical statement into mathematical statement and the calculation is followed by suitable geometric formulae.

Calculation:

Given,

The area of a rectangle =48Â in2

Here,

x is the width and

y is the length

The area of the rectangle A=lw

48=(x)(y)

48=xy

Divide by x on both sides,

48x=xyx

48x=y

Thus, the perimeter of the rectangle P=2l+2

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