STATISTICS F/BUSINESS+ECONOMICS-TEXT
13th Edition
ISBN: 9781305881884
Author: Anderson
Publisher: CENGAGE L
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Textbook Question
Chapter 8.2, Problem 22E
Marvel Studio’s motion picture Guardians of the Galaxy opened over the first two days of the 2014 Labor Day weekend to a record-breaking $94.3 million in ticket sales revenue in North America (The Hollywood Reporter, August 3, 2014). The ticket sales revenue in dollars for a sample of 30 theaters is as follows.
- a. What is the 95% confidence
interval estimate for themean ticket sales revenue per theater? Interpret this result. - b. Using the movie ticket price of $8.11 per ticket, what is the estimate of the mean number of customers per theater?
- c. The movie was shown in 4080 theaters. Estimate the total number of customers who saw Guardians of the Galaxy and the total box office ticket sales for the weekend.
Expert Solution & Answer
Trending nowThis is a popular solution!
Students have asked these similar questions
In a survey of 600 personnel directors, 40% thought that they would be hiring new personnel over the next three months.
(a) Construct a 97% confidence interval for the proportion of all personnel directors planning to hire personnel over the next three months?
(b) What is margin of error used in (a)?
(c) Find the necessary sample size, if they wish to be accurate within 3% of the true proportion.
In a situation where the sample size was decreased from 39 to 29 in a normally distributed data set, what would be the impact on the confidence interval?
In a study by Sallie Mae and Gallup, 323 of the 569respondents said that they paid for their education by taking out student loans. Find a 95% confidence interval for the proportion of students who paid for their education by taking out student loans.
Chapter 8 Solutions
STATISTICS F/BUSINESS+ECONOMICS-TEXT
Ch. 8.1 - A simple random sample of 40 items resulted in a...Ch. 8.1 - A simple random sample of 50 items from a...Ch. 8.1 - A simple random sample of 60 items resulted in a...Ch. 8.1 - A 95% confidence interval for a population mean...Ch. 8.1 - Data were collected on the amount spent by 64...Ch. 8.1 - In an attempt to assess total daily travel taxes...Ch. 8.1 - The average annual cost of the first year of...Ch. 8.1 - Studies show that massage therapy has a variety of...Ch. 8.1 - The mean cost to repair the smoke and fire damage...Ch. 8.1 - Costs are rising for all kinds of medical care....
Ch. 8.2 - For a t distribution with 16 degrees of freedom,...Ch. 8.2 - Find the t value(s) for each of the following...Ch. 8.2 - The following sample data are from a normal...Ch. 8.2 - A simple random sample with n = 54 provided a...Ch. 8.2 - Sales personnel for Skillings Distributors submit...Ch. 8.2 - A sample containing years to maturity and yield...Ch. 8.2 - The International Air Transport Association...Ch. 8.2 - Older people often have a hard time finding work....Ch. 8.2 - The mean cost of a meal for two in a mid-range...Ch. 8.2 - The average annual premium for automobile...Ch. 8.2 - Health insurers are beginning to offer...Ch. 8.2 - Marvel Studios motion picture Guardians of the...Ch. 8.3 - How large a sample should be selected to provide a...Ch. 8.3 - The range for a set of data is estimated to be 36....Ch. 8.3 - Refer to the Scheer Industries example in Section...Ch. 8.3 - The U.S. Energy Information Administration (US...Ch. 8.3 - Annual starting salaries for college graduates...Ch. 8.3 - Many medical professionals believe that eating too...Ch. 8.3 - Customers arrive at a movie theater at the...Ch. 8.3 - There has been a trend toward less driving in the...Ch. 8.4 - A simple random sample of 400 individuals provides...Ch. 8.4 - A simple random sample of 800 elements generates a...Ch. 8.4 - In a survey, the planning value for the population...Ch. 8.4 - At 95% confidence, how large a sample should be...Ch. 8.4 - The Consumer Reports National Research Center...Ch. 8.4 - According to statistics reported on CNBC, a...Ch. 8.4 - One of the questions on a survey of 1000 adults...Ch. 8.4 - According to Franchise business review, over 50%...Ch. 8.4 - In 16% of all homes with a stay-at-home parent,...Ch. 8.4 - For many years businesses have struggled with the...Ch. 8.4 - Fewer young people are driving. In 1983, 87% of...Ch. 8.4 - A poll for the presidential campaign sampled 491...Ch. 8.4 - The Pew Research Center Internet Project,...Ch. 8 - A sample survey of 54 discount brokers showed that...Ch. 8 - A survey conducted by the American Automobile...Ch. 8 - The 92 million Americans of age 50 and over...Ch. 8 - Russia has recently started a push for stronger...Ch. 8 - The Health Care Cost Institute tracks health care...Ch. 8 - A recent article reported that there are...Ch. 8 - Mileage tests are conducted for a particular model...Ch. 8 - In developing patient appointment schedules, a...Ch. 8 - Annual salary plus bonus data for chief executive...Ch. 8 - The National Center for Education Statistics...Ch. 8 - A USA Today/CNN/Gallup survey of 369 working...Ch. 8 - The Pew Research Center has conducted extensive...Ch. 8 - A survey of 750 likely voters in Ohio was...Ch. 8 - The Centers for Disease Control reported the...Ch. 8 - A well-known bank credit card firm wishes to...Ch. 8 - Workers in several industries were surveyed to...Ch. 8 - Although airline schedules and cost are important...Ch. 8 - Young Professional Magazine Young Professional...Ch. 8 - Gulf Real Estate Properties Gulf Real Estate...Ch. 8 - Metropolitan Research, Inc. Metropolitan Research,...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.Similar questions
- What is meant by the sample space of an experiment?arrow_forwardRefer to the accompanying data set of 20 randomly selected presidents. Treat the data as a sample and find the proportion of presidents who were taller than their opponents. Use that result to construct a 95% confidence interval estimate of the population percentage. Based on the result, does it appear that greater height is an advantage for presidential candidates? Why or why not? Construct a 95% confidence interval estimate of the percentage of presidents who were taller than their opponents. PRESIDENT HEIGHT HEIGHT OPPMcKinley 170 178Lincoln 193 188Reagan 185 177Taft 182 178Harrison 173 168Van Buren 168 180Harding 183 178Eisenhower 179 178Taylor 173 174Garfield 183 187J. Kennedy 183 182Harrison 168 180J. Q. Adams 171 191Clinton 188 188Nixon 182 180Johnson 192 180Hoover 182 180T. Roosevelt 178 175Buchanan 183 175Polk 173 185arrow_forwardUse the accompanying Grade Point Averages data to find 90%, 95%, and 99% confidence intervals for the mean GPA.arrow_forward
- Suppose that a safety group surveyed 1,100 drivers. Among those surveyed, 65% said that careless or aggressive driving was the biggest threat on the road, and 25% said that cell phone usage by other drivers was the driving behavior that annoyed them the most. Based on these data and assuming that the sample was a simple random sample, construct and interpret a 95% confidence interval estimate for the true proportion in the population of all drivers who are annoyed by cell phone users. The confidence interval estimate is ??––––––??> (Round to three decimal places as needed. Use ascending order.) Interpret the confidence interval estimate. A. There is a 0.95 probability that the population proportion of drivers who are annoyed by cell phone users is in the interval. B. There is 95% confidence that the population proportion of drivers who are annoyed by cell phone users is in the interval. C. There is 95% confidence that the population proportion…arrow_forwardIn a situation where the sample size was decreased from 39 to 29, what would be the impact on the confidence interval?arrow_forwardhe Pew Social Media Update 2014 surveyed 1,597 adult internet users on which social media websites they use. Of the users surveyed, 1,134 responded "yes" when asked if they use Facebook. Find the margin of error for the confidence interval for the population proportion with a 95% confidence level. z0.10 z0.05 z0.025 z0.01 z0.005 1.282 1.645 1.960 2.326 2.576arrow_forward
- An environmental science teacher at a high school with a large population of students wanted to estimate the proportion of students at the school who regularly recycle plastic bottles. The teacher selected a random sample of students at the school to survey. Each selected student went into the teacher’s office, one at a time, and was asked to respond yes or no to the following question. Based on the responses, a 95 percent confidence interval for the proportion of all students at the school who would respond yes to the question was calculated as (0.584, 0.816 ). (b) Given the method used by the environmental science teacher to collect the responses, explain how bias might have been introduced and describe how the bias might affect the point estimate of the proportion of all students at the school who would respond yes to the question.arrow_forwardAn environmental science teacher at a high school with a large population of students wanted to estimate the proportion of students at the school who regularly recycle plastic bottles. The teacher selected a random sample of students at the school to survey. Each selected student went into the teacher’s office, one at a time, and was asked to respond yes or no to the following question. Based on the responses, a 95 percent confidence interval for the proportion of all students at the school who would respond yes to the question was calculated as (0.584, 0.816 ). (a) How many students were in the sample selected by the environmental science teacher?arrow_forwardAn environmental science teacher at a high school with a large population of students wanted to estimate the proportion of students at the school who regularly recycle plastic bottles. The teacher selected a random sample of students at the school to survey. Each selected student went into the teacher’s office, one at a time, and was asked to respond yes or no to the following question. Based on the responses, a 95 percent confidence interval for the proportion of all students at the school who would respond yes to the question was calculated as (0.584, 0.816 ). (c) The statistics teacher at the high school was concerned about the potential bias in the survey. To obtain a potentially less biased estimate of the proportion, the statistics teacher used an alternate method for collecting student responses. A random sample of 300 students was selected, and each student was given the following instructions on how to respond to the question. • In private, flip a fair coin. • If heads, you…arrow_forward
arrow_back_ios
arrow_forward_ios
Recommended textbooks for you
Glencoe Algebra 1, Student Edition, 9780079039897...AlgebraISBN:9780079039897Author:CarterPublisher:McGraw Hill
College Algebra (MindTap Course List)AlgebraISBN:9781305652231Author:R. David Gustafson, Jeff HughesPublisher:Cengage Learning
Glencoe Algebra 1, Student Edition, 9780079039897...
Algebra
ISBN:9780079039897
Author:Carter
Publisher:McGraw Hill
College Algebra (MindTap Course List)
Algebra
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:Cengage Learning
Sampling Methods and Bias with Surveys: Crash Course Statistics #10; Author: CrashCourse;https://www.youtube.com/watch?v=Rf-fIpB4D50;License: Standard YouTube License, CC-BY
Statistics: Sampling Methods; Author: Mathispower4u;https://www.youtube.com/watch?v=s6ApdTvgvOs;License: Standard YouTube License, CC-BY