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Chapter 8.2, Problem 23E
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### Elementary Geometry For College St...

7th Edition
Alexander + 2 others
ISBN: 9781337614085

#### Solutions

Chapter
Section
BuyFindarrow_forward

### Elementary Geometry For College St...

7th Edition
Alexander + 2 others
ISBN: 9781337614085
Textbook Problem

# Find the ratio A 1 A 2 of the areas of two similar triangles ifa) the ratio of the lengths of the corresponding sides is S 1 S 2 = 3 2 .b) the lengths of the sides of the first triangle are 6 in., 8 in., and 10 in., and those of the second triangle are 3 in., 4 in., and 5 in.

To determine

(a)

To find:

The ratio of the areas of two similar triangles

Explanation

Formula Used:

The ratio of the areas of two similar triangles equals the square of the ratio of the lengths of any two corresponding sides; that is, A1A2=(a1a2)2.

Calculation:

The ratio of the lengths of the corresponding sides is S1S2=32

To determine

(b)

To find:

The ratio A1A2 of the areas of two similar triangles.

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